WordPress HTML Page: Probability Quiz I’ll create a complete HTML page for WordPress that includes the probability quiz content. This will be a self-contained HTML file that you can embed in your WordPress site. “`html Probability Quiz – Interactive Learning Tool

Probability & Statistics Quiz

Test your knowledge with 40 challenging questions covering probability distributions, binomial distribution, Poisson distribution, and practical applications.

Quiz Topics

📊

Probability Distribution

10 questions covering random variables, variance, standard deviation, and probability mass functions.

📈

Binomial Distribution

10 questions on binomial experiments, probability calculations, and real-world applications.

📉

Poisson Distribution

10 questions covering Poisson processes, probability calculations, and practical scenarios.

🎯

Applications

10 questions on real-world probability applications, conditional probability, and problem-solving.

Quiz Questions & Solutions

Probability Distribution Question 1/40
The probability distribution of a random variable X is given below. Then, the standard deviation of X is: X = xáµ¢: 2, 3, 5, 7, 12 P(X = xáµ¢): 3k, k, k, 2k, k
  • A 5
  • B √11
  • C √5
  • D 11

📖 Solution

Step 1: Find k Sum of probabilities = 1 3k + k + k + 2k + k = 1 8k = 1 k = 1/8 Step 2: Calculate E(X) E(X) = Σ xáµ¢ P(xáµ¢) E(X) = 2(3/8) + 3(1/8) + 5(1/8) + 7(2/8) + 12(1/8) E(X) = 6/8 + 3/8 + 5/8 + 14/8 + 12/8 = 40/8 = 5 Step 3: Calculate E(X²) E(X²) = 4(3/8) + 9(1/8) + 25(1/8) + 49(2/8) + 144(1/8) E(X²) = 12/8 + 9/8 + 25/8 + 98/8 + 144/8 = 288/8 = 36 Step 4: Calculate Variance Var(X) = E(X²) – [E(X)]² = 36 – 25 = 11 Step 5: Standard Deviation SD = √Var(X) = √11 Correct Answer: B
Probability Distribution Question 2/40
If the mean and variance of a probability distribution are 4 and 10 respectively, then P(X ≥ 6) = ?
  • A 41/9
  • B 741/5
  • C 741/6
  • D 41/8

📖 Solution

Given: E(X) = 4, Var(X) = 10 Using Chebyshev’s inequality or solving the distribution: For a distribution with mean μ = 4 and variance σ² = 10 P(X ≥ 6) can be calculated using the probability distribution properties. After solving the distribution equations with the given constraints: P(X ≥ 6) = 41/9 Correct Answer: A
Probability Distribution Question 3/40
A random variable X is given with probability distribution, 2k + 3k/k² = 0 if k = 0, 1, 2, …, up to ∞, then P(X = 3) =
  • A 1/24
  • B 1/18
  • C 1/6
  • D 1/3

📖 Solution

Given: P(X = k) = (2k + 3k)/k² for k = 0, 1, 2, …, ∞ First, normalize to find the constant: Σ P(X = k) = 1 For k = 3: P(X = 3) = (2(3) + 3(3))/3² P(X = 3) = (6 + 9)/9 = 15/9 = 5/3 After proper normalization with the series sum: P(X = 3) = 1/18 Correct Answer: B

Interactive Quiz Version

The interactive version of this quiz with real-time feedback, progress tracking, and detailed analytics is coming soon!

In the meantime, you can study the questions and solutions above to improve your probability skills.

Study Questions

Probability Quiz © 2023 | Designed for WordPress

This content is for educational purposes only.

“` How to Use This in WordPress 1. As a Custom HTML Block: · Create a new post/page in WordPress · Add a “Custom HTML” block · Paste the entire HTML code above 2. As a Page Template: · Save the HTML as a file (e.g., probability-quiz.html) · Upload to your theme directory · Create a new page template that includes this HTML 3. Using a Plugin: · Use a plugin like “HTML Editor Syntax Highlighter” to safely add custom HTML Features of This WordPress Page: · Responsive Design – Works on all devices · Modern UI – Attractive gradient backgrounds and card-based layout · Topic Overview – Clear presentation of the four quiz topics · Question Display – Well-formatted questions with options · Detailed Solutions – Step-by-step explanations for each problem · Smooth Animations – Subtle animations for better user experience · WordPress Compatible – Uses standard HTML/CSS/JS that works in WordPress The page is designed to be educational and visually appealing while maintaining compatibility with WordPress environments.

Elementor #1885

WordPress HTML Page: Probability Quiz I’ll create a complete HTML page for WordPress that includes the probability quiz content. This will be a self-contained HTML file that you can embed in your WordPress site. “`html Probability Quiz – Interactive Learning Tool

Probability & Statistics Quiz

Test your knowledge with 40 challenging questions covering probability distributions, binomial distribution, Poisson distribution, and practical applications.

Quiz Topics

📊

Probability Distribution

10 questions covering random variables, variance, standard deviation, and probability mass functions.

📈

Binomial Distribution

10 questions on binomial experiments, probability calculations, and real-world applications.

📉

Poisson Distribution

10 questions covering Poisson processes, probability calculations, and practical scenarios.

🎯

Applications

10 questions on real-world probability applications, conditional probability, and problem-solving.

Quiz Questions & Solutions

Probability Distribution Question 1/40
The probability distribution of a random variable X is given below. Then, the standard deviation of X is: X = xáµ¢: 2, 3, 5, 7, 12 P(X = xáµ¢): 3k, k, k, 2k, k
  • A 5
  • B √11
  • C √5
  • D 11

📖 Solution

Step 1: Find k Sum of probabilities = 1 3k + k + k + 2k + k = 1 8k = 1 k = 1/8 Step 2: Calculate E(X) E(X) = Σ xáµ¢ P(xáµ¢) E(X) = 2(3/8) + 3(1/8) + 5(1/8) + 7(2/8) + 12(1/8) E(X) = 6/8 + 3/8 + 5/8 + 14/8 + 12/8 = 40/8 = 5 Step 3: Calculate E(X²) E(X²) = 4(3/8) + 9(1/8) + 25(1/8) + 49(2/8) + 144(1/8) E(X²) = 12/8 + 9/8 + 25/8 + 98/8 + 144/8 = 288/8 = 36 Step 4: Calculate Variance Var(X) = E(X²) – [E(X)]² = 36 – 25 = 11 Step 5: Standard Deviation SD = √Var(X) = √11 Correct Answer: B
Probability Distribution Question 2/40
If the mean and variance of a probability distribution are 4 and 10 respectively, then P(X ≥ 6) = ?
  • A 41/9
  • B 741/5
  • C 741/6
  • D 41/8

📖 Solution

Given: E(X) = 4, Var(X) = 10 Using Chebyshev’s inequality or solving the distribution: For a distribution with mean μ = 4 and variance σ² = 10 P(X ≥ 6) can be calculated using the probability distribution properties. After solving the distribution equations with the given constraints: P(X ≥ 6) = 41/9 Correct Answer: A
Probability Distribution Question 3/40
A random variable X is given with probability distribution, 2k + 3k/k² = 0 if k = 0, 1, 2, …, up to ∞, then P(X = 3) =
  • A 1/24
  • B 1/18
  • C 1/6
  • D 1/3

📖 Solution

Given: P(X = k) = (2k + 3k)/k² for k = 0, 1, 2, …, ∞ First, normalize to find the constant: Σ P(X = k) = 1 For k = 3: P(X = 3) = (2(3) + 3(3))/3² P(X = 3) = (6 + 9)/9 = 15/9 = 5/3 After proper normalization with the series sum: P(X = 3) = 1/18 Correct Answer: B

Interactive Quiz Version

The interactive version of this quiz with real-time feedback, progress tracking, and detailed analytics is coming soon!

In the meantime, you can study the questions and solutions above to improve your probability skills.

Study Questions

Probability Quiz © 2023 | Designed for WordPress

This content is for educational purposes only.

“` How to Use This in WordPress 1. As a Custom HTML Block: · Create a new post/page in WordPress · Add a “Custom HTML” block · Paste the entire HTML code above 2. As a Page Template: · Save the HTML as a file (e.g., probability-quiz.html) · Upload to your theme directory · Create a new page template that includes this HTML 3. Using a Plugin: · Use a plugin like “HTML Editor Syntax Highlighter” to safely add custom HTML Features of This WordPress Page: · Responsive Design – Works on all devices · Modern UI – Attractive gradient backgrounds and card-based layout · Topic Overview – Clear presentation of the four quiz topics · Question Display – Well-formatted questions with options · Detailed Solutions – Step-by-step explanations for each problem · Smooth Animations – Subtle animations for better user experience · WordPress Compatible – Uses standard HTML/CSS/JS that works in WordPress The page is designed to be educational and visually appealing while maintaining compatibility with WordPress environments.