Table of Content 

Who developed the Binomial Theorem?
The journey of binomial started since the ancient times. Gereman Euclid , in 4^{th} century B.C, has given one of the special case of binomial theorem. Since then, many research work is going on and lot of advancement had been done till date. One of the biggest contributor in binomial theorem is considered as Persian mathematician AlKaraji. He has explained the binomial coefficients with the triangular pattern. He also proved the binomial theorem and the pascal’s triangle.
What is the definition of Binomial in math? Explain Binomial Expression?
The word binomial is a special case of the word – “Polynomial”. Polynomial means an algebraic expression containing two or more algebraic terms. So, the binomial is also an algebraic expression containing exactly two different terms.
So, we can define binomial expression as an algebraic expression consisting of two different terms. Here, in its definition, the word different terms is very important to note. Different terms here means either the two terms should have different variables or the different powers on its variable.
Example
x + y, x^{2} + y^{3}, x + x^{2 }are the expression having two different terms and thus are categorized as binomial expression. Whereas, x + 2x or x^{2}y + 2 x^{2}y can be simplified into one terms and thus are not the example of binomial expression.
What is Binomial Theorem?
Binomial Theorem, in algebra, focuses on the expansion of exponents or powers on a binomial expression. This theorem was given by newton where he explains the expansion of (x + y)^{n} for different values of n.
As per his theorem, the general term in the expansion of (x + y)^{n} can be expressed in the form of px^{q}y^{r}, where q and r are the nonnegative integers and also satisfies q + r = n. Here, ‘p’ is called as the binomial coefficient.
What is (a + b)^{n}?
In (a + b)^{n}, a + b is the binomial and thus the expansion of (a + b)^{n }can be easily calculated by the used of binomial theorem. But let’s here understand the binomial theorem from the basic level. Here, we will understand how the formula of binomial expansion is derived?
If we closely examine the expansion of (a + b) for different exponents, we observe that,
For (a + b)^{0} = 1
For (a + b)^{1 }= a + b
For (a + b)^{2 }= a^{2} + 2ab + b^{2}
For (a + b)^{3} = a^{3 }+ 3a^{2}b + 3ab^{2} + b^{3}
For (a + b)^{4} = a^{4} + 4a^{3}b + 6a^{2}b^{2} + 4ab^{3 }+ b^{4}
From the above expansion, we can note few important properties of its expansion
 The number of terms in the expansion of (a + b)^{n} is n + 1 that is, if n = 3, the number of terms will be 3 + 1 = 4 and so on.
 The power of a starts from n and decreases till it becomes 0.
 Similarly, the power of b starts from 0 and increases till n
 The binomial coefficients of the terms equidistant from the beginning and the end are equal. For Example, in (a + b)^{4} the binomial coefficient of a^{4} & b^{4}, a^{3}b & ab^{3 }are equal
 The sum of the powers of its variables on any term equal to nin in a binomial expansion, just note that the binomials coefficients are nothing but the values of ^{n}Cr for different values of r.
Thus, we can now generalize the binomial theorem for any nonnegative power n.
(x + y)^{n} = ^{n}C_{0}x^{n} + ^{n}C_{1}x^{n1}y + ^{n}C_{2}x^{n2}y^{2} + … + ^{n}C_{r}x^{nr}y^{r} + … + ^{n}C_{n}x^{nn}y^{n}.
From the above equation, we observe that
First term, T_{1} = ^{n}C_{0}x^{n}
Second term, T_{2} = ^{n}C_{1}x^{n1}y^{1}
Third term, T_{3} = ^{n}C_{2}x^{n2}y^{2}
So the general term in the expansion of (x + y)^{n} is
T_{r+1} = ^{n}C_{r}x^{nr}y^{r}
How many terms in the expansion of (x + y + z + w)^{10 }have?
Given problem is an expansion of quadrinomial or a polynomial having four terms. To understand the concept behind this problem, let’s go back to one of the very important property of binomial theorem. It says that, the sum of the powers of its variables on any term is equals to n, where n is the exponent on (x + y).
Thus, if we see the expansion of (x + y)^{n}
(x + y)^{n} = ^{n}C_{0}x^{n} + ^{n}C_{1}x^{n1}y + ^{n}C_{2}x^{n2}y^{2} + … + ^{n}C_{r}x^{nr}y^{r} + … + ^{n}C_{n}x^{nn}y^{n}.
Here, we can see that, the power n is being distributed to the variables x and y in every permutation. Thus, we can relate this distribution with the coin – beggar’s method of permutation and combination.
As per the coin – beggar’s method, the number of ways to distribute n identical coins to p beggar’s will be ^{n + p 1}C_{p1}.
In our case, number of coins is the exponent of any polynomial and number of beggar’s is the number of terms in the polynomial.
Thus for (x + y + z + w)^{10}, we have, n = 10 and p = 4
So, the number of terms in its expansion will be = ^{10+4–1}C_{41 }= ^{13}C_{3}
This method can also be verified for the binomial expansion, where we have n exponent and p = 2. So, the number of terms = ^{n+1}C_{1} = n+1 terms.
What is the binomial coefficient?
In (a + b)^{2} = 1a^{2} + 2ab + 1b^{2}
1, 2 and 1 are called as the binomial coefficients of a^{2}, ab and b^{2} respectively.
Similarly, in (a + b)^{3} = 1a^{3} + 3a^{2}b + 3ab^{2 }+ 1b^{3}
1, 3, 3 and 1 are called as the binomial coefficients of a^{3}, a^{2}b, ab^{2} and b^{3 }respectively.
So, In general, in the expansion of (x + y)^{n}
(x + y)^{n} = ^{n}C_{0}x^{n} + ^{n}C_{1}x^{n1}y + ^{n}C_{2}x^{n2}y^{2} + … + ^{n}C_{r}x^{nr}y^{r} + … + ^{n}C_{n}x^{nn}y^{n}.
all the terms have a constant multiplied with the variables in the form of ^{n}C_{r}. These ^{n}C_{r} are called as the binomial coefficients of different terms (depending upon the value of r).
One more important point to note from here, is the sum of the binomial coefficients can be easily calculated just by replacing the variables to 1.
Example
The sum of the binomial coefficients of (x + y)^{n} will be calculated as follows:
Put x = 1 and y = 1 in the expansion of (x + y)^{n}, we get
(1 + 1)^{n} = 2^{n} = ^{n}C_{0} + ^{n}C_{1} + ^{n}C_{2} + … + ^{n}C_{r} + … + ^{n}C_{n}
How do you use Pascal's triangle?
Pascal’s triangle is named after the French mathematician Blaise Pascal. Pascal’s triangle is a triangular arrangement of binomial coefficients for the expansion of different powers.
Below is the pascal’s triangle for expansion till the exponent five.
What is the binomial series?
Binomial series is a special series in mathematics, also called as the maclaurin series.
This series is a special case of the binomial theorem, where x = 1 and y = x
Binomial Series:
(1 + x)^{n} = ^{n}C_{0} + ^{n}C_{1}x + ^{n}C_{2}x^{2} + …… ^{n}C_{r}x^{r} + …. + ^{n}C_{n}x^{n}
Depending upon the values of x and n, the series can be converging or diverging.
How to apply Binomial Theorem if n is negative or fractional?
The Binomial Theorem for the expansion of (x + y)^{n} where n ∉ I^{+ }will be expanded as,
So, the general term here will be,
Note: In this case, we can’t find the binomial coefficients using ^{n}C_{r} directly, as this is not defined for negative n.
For (a + x)^{n} where n ∉ I^{+},
In this case, where n is non positive integer, the series will converge only for (x/a) <1. But at the same time, the number of terms will be infinite i.e. infinite series.
Similarly for (1 + x)^{n} where n ∉ I^{+},
Above series converges for x < 1
From the above series, we can get few important series which must be remembered as a formula.
 (1 + x)^{1 }= 1 – x + x^{2} – x^{3} + x^{4}  ……..∞
 (1  x)^{1 }= 1 + x + x^{2} + x^{3} + x^{4}  ……..∞
 (1 + x)^{2 }= 1 – 2x + 3x^{2} – 4x^{3} + 5x^{4}  ……..∞
 (1  x)^{2 }= 1 + 2x + 3x^{2 }+ 4x^{3} + 5x^{4}  ……..∞
How to find the term independent of x?
Term independent of ‘x’ here means that term in the binomial expansion which does not have any variable x involved in it.
Example
(x + y)^{2} = x^{2} + 2xy + y^{2}, the third term that is, y^{2} is the term which is independent of ‘x’, while the first term that is, x^{2} is the term independent of y.
Example
(x + y)^{3} = x^{3 }+ 3x^{2}y + 3xy^{2} + y^{3}.
Here, the first term is independent of y and the fourth term is independent of x. Second and fourth terms involves both the variables x and y and thus are not independent of neither x or y.
Now, let’s learn – How to find the independent term in binomial expansion having any power.
Follow the below steps to find it:
 For the given binomial with any power, write down its general term.
 Combine all the ‘x’ terms using the laws of exponent (if not combine).
 Equate the power or indices of ‘x’ to be zero to find the value of variable ‘r’.
 After knowing r, if r is positive integer then (T_{r+1})^{th} term will be the term independent of x otherwise no such term exists.
If you just follow the above steps, you can easily find all such terms. See below example to understand the same.
Example
Which term is independent of x in the expansion of (x – x^{2})10
Step 1: Writing its general term,
T_{r+1} = ^{10}C_{r}x^{10r }(1)r(x2)^{r}
Step 2: Now combining all the x terms,
T_{r+1} = ^{10}C_{r}x^{10r + 2r }(1)^{r }= ^{10}C_{r}x^{10 + r }(1)^{r}
Step 3: Equating the power of x to zero
10 + r = 0 that is, r = 10 which is not a positive integer.
Thus, no such term exists.
Example
Which term is independent of x in the expansion of (x – 1/x)^{20}?
Step 1: Writing its general term,
T_{r+1} = ^{20}C_{r}x^{20r }(1)r(1/x)^{r}
Step 2: Now combining all the x terms,
T_{r+1} = ^{20}C_{r}x^{20r  r }(1)^{r }= ^{20}C_{r}x^{20  2r }(1)^{r}
Step 3: Equating the power of x to zero
20  2r = 0 that is, r = 10 which is a positive integer.
Thus, r+1 = 11^{th} term is independent of x.
This method is also helpful in finding any term or its coefficient having specific power of x. For example, in the example 4, if we are asked to find the coefficient of x^{15}, we will solve as follows:
We have, T_{r+1} = ^{10}C_{r}x^{10r + 2r }(1)^{r }= ^{10}C_{r}x^{10 + r }(1)^{r}
For x^{15}, we should equate the power of x to 15
that is, 10 + r = 15
thus, r = 5 that is, 6^{th} term.
So, the coefficient = T_{6} = ^{10}C_{5}
Recall of Bionomial Theorem
If x, y ∈ R and n ∈ N, then the binomial theorem states that
(x+y)^{n} = ^{n}C_{0}x^{n} + ^{n}C_{1 }x^{n1}y+ ^{n}C_{2} x^{n2 }y^{2} +…… … .. + ^{n}C_{r}x^{nr }y^{r} + ….. + ^{n}C_{n}y^{n}
which can be written as Σ^{n}C_{r}x^{nr}y^{r}. This is also called as the binomial theorem formula which is used for solving many problems.
 Some chief properties of binomial expansion of the term (x+y)^{n}:
 The number of terms in the expansion is (n+1) i.e. it is one more than the index.
 The sum of indices of x and y is always n.
 The binomial coefficients of the terms which are equidistant from the starting and the end are always equal. The simple reason behind this is
C(n, r) = C(n, nr) which gives C(n, n) C(n, 1) = C(n, n1) C(n, 2) = C(n, n2).
 Such an expansion always follows a simple rule which is:
 The subscript of C i.e. the lower suffix of C is always equal to the index of y.
 Index of x = n – (lower suffix of C).
 The (r +1)^{th}term in the expansion of expression (x+y)^{n} is called the general term and is given by T_{r+1 }= ^{n}C_{r}x^{nr}y^{r}
 The term independent of x is obviously without x and is that value of r for which the exponent of x is zero.
 The middle term of the binomial coefficient depends on thevalue of n. There can be two different cases according to whether n is even or n is odd.
 If n is even, then the total number of terms are odd and in that case there is a single middle term which is (n/2 +1)^{th} and is given by ^{n}C_{n/2 }a^{n/2} x^{n/2}.
 On the other hand, if n is odd, the total number of terms is even and then there are two middle terms [(n+1)/2]^{th}and [(n+3)/2]^{th} which are equal to ^{n}C_{(n1)/2 }a^{(n+1)/2} x^{(n1)/2 }and ^{n}C_{(n+1)/2 }a^{(n1)/2} x^{(n+1)/2}
 The binomial coefficient of the middle term is the greatest binomial coefficient of the expansion.
 Some of the standard binomial theorem formulas which should be memorized are listed below:
 C_{0} + C_{1} + C_{2} + ….. + C_{n}= 2^{n}
 C_{0} + C_{2} + C_{4} + ….. = C_{1} + C_{3} + C_{5} + ……….= 2^{n1}
 3. C_{0}^{2} + C_{1}^{2} + C_{2}^{2} + ….. + C_{n}^{2 }= ^{2n}C_{n} = (2n!)/ n!n!
 4. C_{0}C_{r} + C_{1}C_{r+1} + C_{2}C_{r+2}+ ….. + C_{nr}C_{n}=(2n!)/ (n+r)!(nr)!
 Another result that is applied in binomial theorem problems is ^{n}C_{r} + ^{n}C_{r1} = ^{n+1}C_{r}
 We can also replace ^{m}C_{0} by ^{m+1}C_{0} because numerical value of both is same i.e. 1. Similarly we can replace ^{m}C_{m} by ^{m+1}C_{m+1}.
 Note that (2n!) = 2^{n}. n! [1.3.5. … (2n1)]
 In order to compute numerically greatest term in a binomial expansion of (1+x)^{n}, find T_{r+1 }/ T_{r}= (n – r + 1)x/r. Then put the absolute value of x and find the value of r which is consistent with the inequality T_{r+1 }/ T_{r}> 1.
 If the index n is other than a positive integer such as a negative integer or fraction, then the number of terms in the expansion of (1+x)^{n}is infinite.
 The expansions in ascending powers of x are valid only if x is small. If x is large, i.e. x > 1 then it is convenient to expand in powers of 1/x which is then small.
 The binomial expansion for the nth degree polynomial is given by:
 Following expansions should be remembered for x < 1:
 (1+x)^{1} = 1 – x + x^{2} – x^{3} + x^{4}  ….. ∞
 (1x)^{1} = 1 + x + x^{2}+ x^{3} + x^{4}+ ….. ∞
 (1+x)^{2} = 1 – 2x + 3x^{2} – 4x^{3} + 5x^{4}  ….. ∞
(1x)^{2} = 1 +2x + 3x^{2}+4x^{3} + 5x^{4}+ ….. ∞