Mathematics — Engineering 09 May 2026 · Shift 1
Mathematics
- 1\(\left[\dfrac{1}{5},\,5\right]\)
- 2\([1,\,25]\)
- 3\(\left[\dfrac{1}{5},\,1\right)\)
- 4\([1,\,5)\)
- 1\((0,1)\)
- 2\((-1,1)\)
- 3\((-1,0)\)
- 4\((-1,0)\cup(0,1)\)
- 1\(1\)
- 2\(2\)
- 3\(3\)
- 4\(4\)
- 1\(I\)
- 2\(A\)
- 3\(A^2\)
- 4\(A^T\)
- 1\(|A|\)
- 2\(|B|\)
- 3\(|A+B|\)
- 4\(|A-B|\)
\(A=\{k\mid L \text{ has no solution}\}\), \(B=\{k\mid L \text{ has unique solution}\}\), \(C=\{k\mid L \text{ has infinite solutions}\}\).
\(n(A)+n(B)+n(C)=\)
- 1\(2027\)
- 2\(2026\)
- 3\(2029\)
- 4\(2028\)
- 1\(3\)
- 2\(2\)
- 3\(1\)
- 4\(0\)
\(B=\{z=x+iy \mid -3\le y\le 3,\; x\in\mathbb{N},\; y\in\mathbb{N}\}\),
\(C=A\cap B\), then \(n(C)=\)
- 1\(11\)
- 2\(16\)
- 3\(7\)
- 4\(12\)
- 1\(\alpha\)
- 2\(i\)
- 3\(-i\)
- 4\(i\alpha\)
- 1\(-1\)
- 2\(0\)
- 3\(1\)
- 4\(2\)
- 1\(6\)
- 2\(12\)
- 3\(5\)
- 4\(7\)
- 1\(8,\;12\)
- 2\(12,\;10\)
- 3\(10,\;8\)
- 4\(9,\;11\)
- 1\(2\)
- 2\(16\)
- 3\(8\)
- 4\(12\)
- 1\(25\)
- 2\(35\)
- 3\(297\)
- 4\(105\)
- 1\(5\)
- 2\(1\)
- 3\(7\)
- 4\(3\)
- 1\(105\)
- 2\(66\)
- 3\(69\)
- 4\(83\)
- 1\(\dfrac{3}{5}\)
- 2\(12\)
- 3\(8\)
- 4\(\dfrac{5}{3}\)
- 1\(11879(8!)\)
- 2\(966(8!)\)
- 3\(986(8!)\)
- 4\(494(4!)(8!)\)
- 1even integer and odd integer respectively
- 2odd integer and even integer respectively
- 3both odd integers
- 4both even integers
- 1\(\alpha_{13}\)
- 2\(\beta_{13}\)
- 3\(\alpha_{25}\)
- 4\(\beta_{25}\)
- 1\(13\)
- 2\(36\)
- 3\(2\)
- 4\(1\)
- 1\(\dfrac{\sin(\pi/7)}{7}\)
- 2\(\dfrac{2\pi}{7}\)
- 3\(2\)
- 4\(1\)
- 1\(\dfrac{1}{2}\)
- 2\(\dfrac{\sqrt3}{2}\)
- 3\(\dfrac{3}{5}\)
- 4\(0\)
- 1\(4\)
- 2\(2\)
- 3\(6\)
- 4\(8\)
- 1\(\dfrac{\pi}{6},\dfrac{\pi}{4},\dfrac{\pi}{2},\dfrac{3\pi}{4},\dfrac{5\pi}{6}\)
- 2\(\dfrac{\pi}{3},\dfrac{\pi}{2},\dfrac{2\pi}{3}\)
- 3\(\dfrac{\pi}{6},\dfrac{\pi}{3},\dfrac{2\pi}{3}\)
- 4\(\dfrac{\pi}{4},\dfrac{\pi}{2},\dfrac{3\pi}{4}\)
- 1\(0\)
- 2\(1\)
- 3\(2\)
- 4\(3\)
- 1\([3,\infty)\)
- 2\(\left(0,\dfrac{25}{8}\right)\)
- 3\(\left[3,\dfrac{25}{8}\right]\)
- 4\((-\infty,3]\)
- 1\(-\sqrt3\)
- 2\(\sqrt3\)
- 3\(\sqrt5-\sqrt3\)
- 4\(\sqrt2\)
- 1\(\sqrt{b}\)
- 2\(\sqrt{2R}\sin A\)
- 3\(\sqrt{2R}\)
- 4\(\sqrt{a+c}\)
- 1\(\dfrac{4}{30}\)
- 2\(\dfrac{46}{295}\)
- 3\(\dfrac{30}{295}\)
- 4\(\dfrac{1}{15}\)
- 1\(1\)
- 2\(2\)
- 3\(3\)
- 4\(0\)
- 1\(6\)
- 2\(2\sqrt6\)
- 3\(\sqrt6\)
- 4\(3\sqrt6\)
- 1\([-9,\,15]\)
- 2\([-15,\,9]\)
- 3\((-\infty,\,-15)\)
- 4\(\mathbb{R}-[-11,\,9]\)
- 1\(0\)
- 2\(9[a\;b\;c]\)
- 3\(15[a\;b\;c]\)
- 4\(12[a\;b\;c]\)
| Class interval | 1–7 | 7–13 | 13–19 | 19–25 | 25–31 |
|---|---|---|---|---|---|
| Frequency | 4 | 5 | 3 | 6 | 2 |
- 1\(7\)
- 2\(7.5\)
- 3\(6\)
- 4\(5\)
- 1\(21\)
- 2\(63\)
- 3\(12\)
- 4\(189\)
- 1\(3\)
- 2\(3\)
- 3\(4\)
- 4\(1\)
- 1\(40\)
- 2\(13\)
- 3\(\dfrac{3}{14}\)
- 4\(\dfrac{5}{12}\)
- 1\(3\)
- 2\(4\)
- 3\(5\)
- 4\(7\)
- 1\(1-p\)
- 2\(p\)
- 3\(p^2\)
- 4\(\dfrac{1}{p}\)
- 1\(x^2+y^2-5xy+1=0\)
- 2\(x^2+y^2+5xy-1=0\)
- 3\(x^2+y^2=13\)
- 4\(x^2-y^2=5\)
- 1\(13-\sqrt3\)
- 2\(16+2\)
- 3\(14-2\)
- 4\(15+\sqrt3\)
- 1\(4\)
- 2\(3\)
- 3\(9\)
- 4\(16\)
- 1\(x-4y+1=0\)
- 2\(3x-2y=17\)
- 3\(x+y=9\)
- 4\(x+8y-23=0\)
- 1\(15\)
- 2\(48\)
- 3\(21\)
- 4\(26\)
- 1\(\dfrac{\pi}{4}\)
- 2\(\dfrac{\pi}{3}\)
- 3\(\dfrac{\pi}{6}\)
- 4\(\dfrac{\pi}{2}\)
- 1\((x-5a)^2+y^2=16a^2\)
- 2\((x-4a)^2+y^2=9a^2\)
- 3\((x+7a)^2+y^2=64a^2\)
- 4\((x+a)^2+y^2=4a^2\)
- 1\(8\)
- 2\(7\)
- 3\(5\)
- 4\(4\)
- 1\(5\)
- 2\(4\)
- 3\(\dfrac{12}{5}\)
- 4\(\dfrac{13}{4}\)
- 1\(-10-\sqrt{175}\)
- 2\(-10-\sqrt{75}\)
- 3\(-10-\sqrt{125}\)
- 4\(-10-\sqrt{150}\)
- 1\((0,3)\)
- 2\((2,8)\)
- 3\((-2,-2)\)
- 4\((-4,-7)\)
- 1\(4\)
- 2\(5\sqrt2\)
- 3\(\dfrac{7}{5}\)
- 4\(\dfrac{5}{2}\)
- 1\(4\)
- 2\(8\)
- 3\(12\)
- 4\(6\)
- 1\(y=\dfrac{1}{2}\)
- 2\(x^2+y^2=\dfrac{1}{4}\)
- 3\(x^2+y^2=\dfrac{1}{4}\)
- 4\(y^2=2x\)
- 1\(\dfrac{x^2}{48}+\dfrac{y^2}{45}=1\)
- 2\(\dfrac{x^2}{16}+\dfrac{y^2}{15}=1\)
- 3\(\dfrac{x^2}{24}+\dfrac{y^2}{45}=\dfrac{1}{\sqrt5}\)
- 4\(\sqrt{\dfrac{x^2}{8\sqrt3}}+\sqrt{\dfrac{2y^2}{15\sqrt3}}=\dfrac{1}{\sqrt5}\)
- 1\(\sqrt{5(x-1)^2+9(y-1)^2}=20\)
- 2\(\sqrt{5(x+1)^2+9(y+1)^2}=20\)
- 3\(\sqrt{9(x-1)^2+5(y-1)^2}=20\)
- 4\(\sqrt{9(x+1)^2+5(y+1)^2}=20\)
- 1\(2.25\)
- 2\(2.50\)
- 3\(1.75\)
- 4\(2.00\)
- 1\(13\)
- 2\(5\)
- 3\(20\)
- 4\(8\)
- 1\(13-\sqrt3\)
- 2\(8-\sqrt3\)
- 3\(16+\sqrt3\)
- 4\(7-\sqrt2\)
- 1\(\dfrac{6}{\sqrt{30}}\)
- 2\(\dfrac{4}{\sqrt{30}}\)
- 3\(\dfrac{2}{30}\)
- 4\(\dfrac{8}{30}\)
- 1\(10\)
- 2\(-11\)
- 3\(12\)
- 4\(-9\)
- 1\(5f(0)\)
- 2\(f(0)\)
- 3\(-f(0)\)
- 4\(f(0)\)
Assertion (A): \(|f(x)|g(x)\) is continuous and differentiable at all \(\alpha_i\)’s.
Reason (R): \(\displaystyle\lim_{x\to a}\frac{|x-a|}{x-a}\) does not exist and \(\displaystyle\lim_{x\to a}|x-a|=0\).
The correct answer is
- 1Both (A) and (R) are correct, (R) is the correct explanation of (A)
- 2Both (A) and (R) are correct, (R) is not the correct explanation of (A)
- 3(A) is correct, but (R) is not correct
- 4(A) is not correct, but (R) is correct
- 1\(0\)
- 2\(-5\)
- 3\(4\)
- 4\(6\)
- 1\(1+y\)
- 2\(y\)
- 3\(y\)
- 4\(1-y\)
- 1\(5\sqrt2\)
- 2\(12\sqrt2\)
- 3\(3\)
- 4\(9\)
Statement-II: If L, M, N are respectively the lengths of the tangent, normal and subnormal drawn to a curve at a point \((\alpha,\beta)\), then \((L)(N)=\beta^2 M\).
Which of the following is correct?
- 1Both statements I and II are correct
- 2Statement I is correct but statement II is not correct
- 3Statement I is not correct but statement II is correct
- 4Both statements I and II are not correct
- 1only Rolle’s theorem is applicable, but Lagrange’s mean value theorem is not applicable
- 2Rolle’s theorem is not applicable but Lagrange’s mean value theorem is applicable
- 3Both Rolle’s and Lagrange’s theorems are applicable
- 4Both Rolle’s and Lagrange’s theorems are not applicable
- 1\(-108\)
- 2\(108\)
- 3\(72\)
- 4\(-72\)
- 1\(13\)
- 2\(\dfrac{13}{3}\)
- 3\(\dfrac{5}{13}\)
- 4\(\dfrac{13}{5}\)
- 1\(6,\;5\sqrt3\)
- 2\(6,\;2\sqrt3\)
- 3\(9,\;6\)
- 4\(5,\;3\)
- 1\(x[\sin^{-1}x-\cos^{-1}x]-2\sqrt{1-x^2}+c\)
- 2\(x\!\left[2\sin^{-1}x+\dfrac{\pi}{2}\right]-2\sqrt{1-x^2}+c\)
- 3\(x[\sin^{-1}x-\cos^{-1}x]+2\sqrt{1-x^2}+c\)
- 4\(x\!\left[\dfrac{\pi}{2}+\cos^{-1}x\right]+2\sqrt{1-x^2}+c\)
- 1\(11\)
- 2\(15\)
- 3\(23\)
- 4\(27\)
- 1\(3\)
- 2\(2\)
- 3\(3\)
- 4\(6\)
- 1\(\log|\sin x|+c\)
- 2\(\log|\cos x|+c\)
- 3\(-\operatorname{cosec}^2 x+c\)
- 4\(\tan x+c\)
- 1\(0\)
- 2\(\dfrac{1}{2}\)
- 3\(1\)
- 4\(2\)
- 1\(2\tan^{-1}2\)
- 2\(0\)
- 3\(2\)
- 4\(\tan^{-1}2\)
- 1\(50\)
- 2\(68\)
- 3\(100\)
- 4\(98\)
- 1\(\pi^2+16\)
- 2\(16-\pi^2\)
- 3\(\pi^2-16\)
- 4\(16\pi^2\)
- 1\(-1\)
- 2\(1\)
- 3\(3\)
- 4\(5\)

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