Table of Contents
ToggleMathematics — Engineering 09 May 2026 · Shift 1
Section 1 · 80 Questions · 80 Marks · Correct option highlighted in green
Mathematics
Section 1 · 80 Questions · 80 Marks · Mandatory
Q1+1 / 0
The domain of the real valued function
\[ f(x)=\cos^{-1}\!\left(\log_5\!\left(\frac{x}{5}\right)\right)+\log_5\!\left(\cos^{-1}\!\left(\frac{x}{5}\right)\right) \]
is
- 1\(\left[\dfrac{1}{5},\,5\right]\)
- 2\([1,\,25]\)
- 3\(\left[\dfrac{1}{5},\,1\right)\)
- 4\([1,\,5)\)
Q2+1 / 0
If \(f:\mathbb{R}\to\mathbb{R}\) is a function defined by \(f(x)=|x|\) for all \(x\in\mathbb{R}\) and \(A\) represents the interval \((0,1)\), then \(f^{-1}(A)=\)
- 1\((0,1)\)
- 2\((-1,1)\)
- 3\((-1,0)\)
- 4\((-1,0)\cup(0,1)\)
Q3+1 / 0
If \(S(n):2^n
- 1\(1\)
- 2\(2\)
- 3\(3\)
- 4\(4\)
Q4+1 / 0
If \(A=\begin{bmatrix}\cos\alpha&0&\sin\alpha\\0&1&0\\-\sin\alpha&0&\cos\alpha\end{bmatrix}\) and \(A^2=A^T\) for one value of \(\alpha\in(0,\pi)\), then \(A^3=\)
- 1\(I\)
- 2\(A\)
- 3\(A^2\)
- 4\(A^T\)
Q5+1 / 0
Let \(A\) be a \(3\times3\) matrix such that \(\det(A)=-1\). If \(B^{-1}=\operatorname{Adj}\!\big(A\,\operatorname{Adj}(A^2)\big)\), then \(\det\big((\det A)B\big)=\)
- 1\(|A|\)
- 2\(|B|\)
- 3\(|A+B|\)
- 4\(|A-B|\)
Q6+1 / 0
Consider the system of linear equations (L): \(2x-y-z=-3,\; x+2y+z=4,\; 3x+y+kz=3\). Let \(k\in\mathbb{N}\) and \(1\le k\le 2026\).
\(A=\{k\mid L \text{ has no solution}\}\), \(B=\{k\mid L \text{ has unique solution}\}\), \(C=\{k\mid L \text{ has infinite solutions}\}\).
\(n(A)+n(B)+n(C)=\)
\(A=\{k\mid L \text{ has no solution}\}\), \(B=\{k\mid L \text{ has unique solution}\}\), \(C=\{k\mid L \text{ has infinite solutions}\}\).
\(n(A)+n(B)+n(C)=\)
- 1\(2027\)
- 2\(2026\)
- 3\(2029\)
- 4\(2028\)
Q7+1 / 0
Let \(A\) be a \(3\times3\) matrix. If
\[ A\begin{bmatrix}0\\0\\1\end{bmatrix}=\begin{bmatrix}1\\2\\3\end{bmatrix},\quad
A\begin{bmatrix}1\\0\\1\end{bmatrix}=\begin{bmatrix}1\\0\\-1\end{bmatrix},\quad
A\begin{bmatrix}1\\1\\0\end{bmatrix}=\begin{bmatrix}1\\1\\0\end{bmatrix} \]
then the rank of \((A-I)\) is
- 1\(3\)
- 2\(2\)
- 3\(1\)
- 4\(0\)
Q8+1 / 0
If \(A=\{z=x+iy \mid |z-4|<|z-2| \;\&\; |z-7|>|z-3|\}\),
\(B=\{z=x+iy \mid -3\le y\le 3,\; x\in\mathbb{N},\; y\in\mathbb{N}\}\),
\(C=A\cap B\), then \(n(C)=\)
\(B=\{z=x+iy \mid -3\le y\le 3,\; x\in\mathbb{N},\; y\in\mathbb{N}\}\),
\(C=A\cap B\), then \(n(C)=\)
- 1\(11\)
- 2\(16\)
- 3\(7\)
- 4\(12\)
Q9+1 / 0
\(z_1\) and \(z_2\) are two complex numbers such that \(|z_1-\alpha|=|z_2-\alpha|\) for \(\alpha\in\mathbb{R}\). If \(\operatorname{Arg}(z_1-\alpha)+\operatorname{Arg}(z_2-\alpha)=\dfrac{\pi}{2}\), then \(\dfrac{z_1-\alpha}{z_2-\alpha}=\)
- 1\(\alpha\)
- 2\(i\)
- 3\(-i\)
- 4\(i\alpha\)
Q10+1 / 0
If \(\omega\) is the complex cube root of 1, then
\[ (1+\omega)(1+\omega^2)(1+\omega^4)(1+\omega^5)(1+\omega^7)(1+\omega^8)\cdots 2n \text{ factors} = \]
- 1\(-1\)
- 2\(0\)
- 3\(1\)
- 4\(2\)
Q11+1 / 0
\(m,n,k\) are integers and \(9.5\le n\le 12\). If
\[ \frac{(\cos\theta+i\sin\theta)^m}{(\sin\theta+i\cos\theta)^n}=k(\sin 170^\circ – i\cos 170^\circ), \]
then \(n-m-k=\)
- 1\(6\)
- 2\(12\)
- 3\(5\)
- 4\(7\)
Q12+1 / 0
If \(a\in\mathbb{Z}\) and the equation \((x-a)(x-10)+1=0\) has integral roots, then the values of \(a\) are
- 1\(8,\;12\)
- 2\(12,\;10\)
- 3\(10,\;8\)
- 4\(9,\;11\)
Q13+1 / 0
If \(\alpha,\beta\) are the rational roots and \(l,m\) are the irrational roots of
\[ (x^2-9x+11)^2-(x-4)(x-5)=3, \]
then \(\alpha+\beta+l=\)
- 1\(2\)
- 2\(16\)
- 3\(8\)
- 4\(12\)
Q14+1 / 0
Let \(\alpha,\beta,\gamma,\delta\) be the roots of \(4x^4+8x^3-17x^2-12x+9=0\). If
\(4(\alpha+4)(\beta+4)(\gamma+4)(\delta+4)=k\), then \(k=\)
- 1\(25\)
- 2\(35\)
- 3\(297\)
- 4\(105\)
Q15+1 / 0
The number of real roots of the equation \(x^7+3x^5-13x^3-15x=0\) is
- 1\(5\)
- 2\(1\)
- 3\(7\)
- 4\(3\)
Q16+1 / 0
The number of integral solutions of the equation \(x+y+z=13\) such that \(1\le x\le9,\;0\le y\le9,\;0\le z\le9\) is
- 1\(105\)
- 2\(66\)
- 3\(69\)
- 4\(83\)
Q17+1 / 0
If \(\dfrac{{}^{n-1}C_{r-1}}{{}^{n}C_r}=\dfrac{3}{5}\) and \(\dfrac{{}^{n+1}C_{r+1}}{{}^{n}C_r}=\dfrac{11}{7}\), then
\({}^{n}C_{r+3}\div{}^{r}C_{n/2}=\)
- 1\(\dfrac{3}{5}\)
- 2\(12\)
- 3\(8\)
- 4\(\dfrac{5}{3}\)
Q18+1 / 0
There are 7 men and 5 women in a park. The number of ways of arranging them around a circular path such that 4 particular persons which include 2 particular men and 2 particular women never stand together is
- 1\(11879(8!)\)
- 2\(966(8!)\)
- 3\(986(8!)\)
- 4\(494(4!)(8!)\)
Q19+1 / 0
Let \([t]\) represent the greatest integer less than or equal to \(t\). If \(x=(7\sqrt5+15)^9\) and \(y=(5\sqrt7+13)^{11}\), then \([x]\) and \([y]\) are
- 1even integer and odd integer respectively
- 2odd integer and even integer respectively
- 3both odd integers
- 4both even integers
Q20+1 / 0
If \(\alpha_n\) is the coefficient of \(x^n\) in the expansion of \((1-x)^{-5}\) and \(\beta_n\) is the coefficient of \(x^n\) in the expansion of \((1-x)^4\), then \(\alpha_{12}+\beta_{13}=\)
- 1\(\alpha_{13}\)
- 2\(\beta_{13}\)
- 3\(\alpha_{25}\)
- 4\(\beta_{25}\)
Q21+1 / 0
If \(\dfrac{x^2+1}{(x^4+5x^2+6)(x^6+x^4)}=\dfrac{A}{x^4}+\dfrac{B}{x^2}+\dfrac{C}{x^2+2}+\dfrac{D}{x^2+3}\), then \(A-B=\)
- 1\(13\)
- 2\(36\)
- 3\(2\)
- 4\(1\)
Q22+1 / 0
If \(\theta=\dfrac{11\pi}{7}\), then \(\dfrac{1+\cos 8\theta}{\cot^2 4\theta}+\dfrac{1-\cos 8\theta}{\tan^2 4\theta}=\)
- 1\(\dfrac{\sin(\pi/7)}{7}\)
- 2\(\dfrac{2\pi}{7}\)
- 3\(2\)
- 4\(1\)
Q23+1 / 0
If \(\alpha\) and \(\beta\) are acute angles and \(\cos\alpha(1+\tan\alpha\tan\beta)=1\), then
\(\sin\!\left(\dfrac{\alpha-2\beta}{3}\right)=\)
- 1\(\dfrac{1}{2}\)
- 2\(\dfrac{\sqrt3}{2}\)
- 3\(\dfrac{3}{5}\)
- 4\(0\)
Q24+1 / 0
The number of values of \(\theta\) lying in \([0,2\pi]\) for which \(\sin 3\theta\) attains its maximum when
\[ \left|\sin\theta\,\sin\!\left(\frac{\pi}{3}-\theta\right)\sin\!\left(\frac{\pi}{3}+\theta\right)\right|\le\frac{1}{8} \]
is
- 1\(4\)
- 2\(2\)
- 3\(6\)
- 4\(8\)
Q25+1 / 0
If \(\cos 6\theta+\cos 4\theta+\cos 2\theta+1=0\) for \(0\le\theta\le\pi\), then \(\theta=\)
- 1\(\dfrac{\pi}{6},\dfrac{\pi}{4},\dfrac{\pi}{2},\dfrac{3\pi}{4},\dfrac{5\pi}{6}\)
- 2\(\dfrac{\pi}{3},\dfrac{\pi}{2},\dfrac{2\pi}{3}\)
- 3\(\dfrac{\pi}{6},\dfrac{\pi}{3},\dfrac{2\pi}{3}\)
- 4\(\dfrac{\pi}{4},\dfrac{\pi}{2},\dfrac{3\pi}{4}\)
Q26+1 / 0
The number of real solutions of the equation \(\sin^{-1}(2-x)-2\sin^{-1}x=\pm\dfrac{\pi}{2}\) is
- 1\(0\)
- 2\(1\)
- 3\(2\)
- 4\(3\)
Q27+1 / 0
If \(\alpha\) is a real number and \(2\sinh^2 x-3\cosh x+\alpha=0\) has a solution, then the range of \(\alpha\) is
- 1\([3,\infty)\)
- 2\(\left(0,\dfrac{25}{8}\right)\)
- 3\(\left[3,\dfrac{25}{8}\right]\)
- 4\((-\infty,3]\)
Q28+1 / 0
In a triangle ABC, if \(a=2,\;\sin A=\dfrac{2}{3},\;B=\dfrac{\pi}{3}\), then \(\sqrt5\,b-3c=\)
- 1\(-\sqrt3\)
- 2\(\sqrt3\)
- 3\(\sqrt5-\sqrt3\)
- 4\(\sqrt2\)
Q29+1 / 0
In a triangle ABC, if \((b-c)\cos\dfrac{A}{2}=k\sin\dfrac{B-C}{2}\), then \(\dfrac{k}{\sin A}=\)
- 1\(\sqrt{b}\)
- 2\(\sqrt{2R}\sin A\)
- 3\(\sqrt{2R}\)
- 4\(\sqrt{a+c}\)
Q30+1 / 0
Let \(\vec{OA}=\mathbf{i}+2\mathbf{j}+2\mathbf{k},\;\vec{OB}=3\mathbf{i}+4\mathbf{k}\). If \(x\mathbf{i}+y\mathbf{j}+z\mathbf{k}\) is the vector along the bisector of \(\angle AOB\) and of length 2 units, then a possible value of \(x+y+z\) is
- 1\(\dfrac{4}{30}\)
- 2\(\dfrac{46}{295}\)
- 3\(\dfrac{30}{295}\)
- 4\(\dfrac{1}{15}\)
Q31+1 / 0
If the line \(\vec r=\vec a+t\vec b\) lies on the plane \(\vec r\cdot\vec n=p\), then \(p=\)
- 1\(1\)
- 2\(2\)
- 3\(3\)
- 4\(0\)
Q32+1 / 0
If \(\vec{AB}=\mathbf{i}+\mathbf{j}-2\mathbf{k},\;\vec{CB}=2\mathbf{i}-\mathbf{j}+a\mathbf{k}\;(a\in\mathbb{Z})\) are two sides of a triangle ABC and the angle between these two sides is \(\dfrac{\pi}{3}\), then the length of its third side is
- 1\(6\)
- 2\(2\sqrt6\)
- 3\(\sqrt6\)
- 4\(3\sqrt6\)
Q33+1 / 0
If the shortest distance between the skew lines \(\vec r=\mathbf{i}+\mathbf{j}+\mathbf{k}+t(3\mathbf{i}+2\mathbf{j}+\mathbf{k})\) and \(\vec r=\mathbf{i}-\mathbf{j}+x\mathbf{k}+s(\mathbf{i}+2\mathbf{j}+3\mathbf{k})\) is at most \(2\sqrt6\) units, then all the values of \(x\) lie in the interval
- 1\([-9,\,15]\)
- 2\([-15,\,9]\)
- 3\((-\infty,\,-15)\)
- 4\(\mathbb{R}-[-11,\,9]\)
Q34+1 / 0
\(\vec a,\vec b,\vec c\) are non-coplanar vectors. If \(\vec x=2\vec a+3\vec b+4\vec c,\;\vec y=3\vec a+4\vec b+5\vec c,\;\vec z=4\vec a+5\vec b+6\vec c\), then \([\vec x\;\vec y\;\vec z]=\)
- 1\(0\)
- 2\(9[a\;b\;c]\)
- 3\(15[a\;b\;c]\)
- 4\(12[a\;b\;c]\)
Q35+1 / 0
The mean deviation from the median of the given frequency distribution is
| Class interval | 1–7 | 7–13 | 13–19 | 19–25 | 25–31 |
|---|---|---|---|---|---|
| Frequency | 4 | 5 | 3 | 6 | 2 |
- 1\(7\)
- 2\(7.5\)
- 3\(6\)
- 4\(5\)
Q36+1 / 0
Bag A contains 5 white and 2 black balls. Bag B contains 2 white and 5 black balls. Two balls are randomly chosen from bag A and placed in bag B. Now a ball is drawn randomly from bag B and found that it is white. The probability that the two balls drawn from bag A are of different colour is
- 1\(21\)
- 2\(63\)
- 3\(12\)
- 4\(189\)
Q37+1 / 0
If A, B, C are three mutually exclusive and exhaustive events such that \(P(A):P(B):P(C)=1:1:m\), then
\(P(A\cup B)+P(B\cup C)+P(C\cup A)+P(A\cup B\cup C)=\)
- 1\(3\)
- 2\(3\)
- 3\(4\)
- 4\(1\)
Q38+1 / 0
If \(P(A)=\dfrac{3}{8},\;P(A\mid B)=P(B\mid A)=\dfrac{3}{5}\), then \(P(A\cap B)+P(B)=\)
- 1\(40\)
- 2\(13\)
- 3\(\dfrac{3}{14}\)
- 4\(\dfrac{5}{12}\)
Q39+1 / 0
Probability for a person A to have success in one trial is \(\dfrac{2}{5}\). In 7 Bernoulli trials, if the probability that A has \(k\) successes is to be highest probability, then \(k=\)
- 1\(3\)
- 2\(4\)
- 3\(5\)
- 4\(7\)
Q40+1 / 0
Let \(p\) be the probability of getting a success in one trial and \(0
- 1\(1-p\)
- 2\(p\)
- 3\(p^2\)
- 4\(\dfrac{1}{p}\)
Q41+1 / 0
If \(S=\{(x,y)\mid x=2\cos t+3\sin t,\;y=3\cos t+2\sin t,\;t\in\mathbb{R}\}\), then the points of S lie on the curve
- 1\(x^2+y^2-5xy+1=0\)
- 2\(x^2+y^2+5xy-1=0\)
- 3\(x^2+y^2=13\)
- 4\(x^2-y^2=5\)
Q42+1 / 0
If the coordinate axes are rotated about the origin in the positive direction through an angle \(60^\circ\) to get the transformed equation of \(x^2+y^2-4x-8y+16=0\) as \(x^2+y^2+2Gx+2Fy+C=0\), then \(G+F+C=\)
- 1\(13-\sqrt3\)
- 2\(16+2\)
- 3\(14-2\)
- 4\(15+\sqrt3\)
Q43+1 / 0
\((3a+1)x+(7a+2)y=17a+5\), \(a\) being a parameter, represents a family of concurrent lines. If \(d\) is the distance from the point \((3,1)\) to a line of this family having slope 1, then \(2d^2=\)
- 1\(4\)
- 2\(3\)
- 3\(9\)
- 4\(16\)
Q44+1 / 0
Let a ray of light passing through a point \((7,2)\) reflects on the line \(2x+y=1\) and the reflected ray passes through \((3,10)\). The equation of the incident ray is
- 1\(x-4y+1=0\)
- 2\(3x-2y=17\)
- 3\(x+y=9\)
- 4\(x+8y-23=0\)
Q45+1 / 0
Let ABC be an isosceles triangle. If B is a point on the positive X-axis, \(a=4\sqrt3\), \(c\) is an integer, \(\angle A=120^\circ\) and \(A=(-1,0)\), then the distance of C from the origin is
- 1\(15\)
- 2\(48\)
- 3\(21\)
- 4\(26\)
Q46+1 / 0
One of the pair of lines \(x^2-3y^2-4x-6\sqrt3 y-5=0\) is \(x+by+c=0\;(b<0)\). If the other line intersects the curve \(x^2-5y^2-4x=0\) at two points A and B, then \(\angle AOB=\)
- 1\(\dfrac{\pi}{4}\)
- 2\(\dfrac{\pi}{3}\)
- 3\(\dfrac{\pi}{6}\)
- 4\(\dfrac{\pi}{2}\)
Q47+1 / 0
If a circle inscribed in the parabola \(y^2=4ax\;(a>0)\) passes through its focus, then the equation of that circle is
- 1\((x-5a)^2+y^2=16a^2\)
- 2\((x-4a)^2+y^2=9a^2\)
- 3\((x+7a)^2+y^2=64a^2\)
- 4\((x+a)^2+y^2=4a^2\)
Q48+1 / 0
Let \((-h,-k)\) (h, k integers) be the centre and \(r\) the radius of a circle. If \(3x+4y-24=0,\;3x-4y-32=0\) are two tangents and \(4x+3y-1=0\) is a normal, then \(r+h+k=\)
- 1\(8\)
- 2\(7\)
- 3\(5\)
- 4\(4\)
Q49+1 / 0
Let P be any point on the circle \(x^2+y^2=16\) and \(A=(1,2)\). If the locus of the point which divides the line segment AP in the ratio 3:2 is a circle, then its radius is
- 1\(5\)
- 2\(4\)
- 3\(\dfrac{12}{5}\)
- 4\(\dfrac{13}{4}\)
Q50+1 / 0
If the line \(4x-3y+c=0\;(c<-10)\) makes an intercept of length 10 units on the circle \(x^2+y^2-2x+4y-23=0\), then \(c=\)
- 1\(-10-\sqrt{175}\)
- 2\(-10-\sqrt{75}\)
- 3\(-10-\sqrt{125}\)
- 4\(-10-\sqrt{150}\)
Q51+1 / 0
The tangent drawn at a point P on the circle \(x^2+y^2+6x+6y-2=0\) cuts the line \(5x-2y+6=0\) at Q. If \(PQ=5\), then a point Q having integral coordinates is
- 1\((0,3)\)
- 2\((2,8)\)
- 3\((-2,-2)\)
- 4\((-4,-7)\)
Q52+1 / 0
If two vertices of a quadrilateral are the centres of the circles \(S\equiv x^2+y^2-2x-2y-2=0,\;S’\equiv x^2+y^2-6x-6y+14=0\) and the other two vertices are the points of intersection of S=0 and S’=0, then the area of the quadrilateral is
- 1\(4\)
- 2\(5\sqrt2\)
- 3\(\dfrac{7}{5}\)
- 4\(\dfrac{5}{2}\)
Q53+1 / 0
\(y=4\) is the directrix of the parabola \(x^2+8x+12y+k=0\). If \(l\) is the length of its latus rectum, then \(l-k=\)
- 1\(4\)
- 2\(8\)
- 3\(12\)
- 4\(6\)
Q54+1 / 0
\((1,1)\) is the focus of the parabola \(y^2-4ax-2ay+a^2=0\). If the circles \((x-\alpha)^2+(y-\beta)^2=r^2\) (\(\alpha,\beta\) parameters) touch the X-axis and the axis of the given parabola, then \(\{(\alpha,\beta)\mid\alpha,\beta\in\mathbb{R}\}\) is
- 1\(y=\dfrac{1}{2}\)
- 2\(x^2+y^2=\dfrac{1}{4}\)
- 3\(x^2+y^2=\dfrac{1}{4}\)
- 4\(y^2=2x\)
Q55+1 / 0
The area of the rectangle formed by the tangents drawn at the ends of both major and minor axes of an ellipse is 24. If the eccentricity of the ellipse is \(\dfrac{1}{4}\), then the equation of the ellipse is
- 1\(\dfrac{x^2}{48}+\dfrac{y^2}{45}=1\)
- 2\(\dfrac{x^2}{16}+\dfrac{y^2}{15}=1\)
- 3\(\dfrac{x^2}{24}+\dfrac{y^2}{45}=\dfrac{1}{\sqrt5}\)
- 4\(\sqrt{\dfrac{x^2}{8\sqrt3}}+\sqrt{\dfrac{2y^2}{15\sqrt3}}=\dfrac{1}{\sqrt5}\)
Q56+1 / 0
The centre of the ellipse lies on the lines \(2x+3y=5\) and \(x+3y=4\). If the eccentricity is \(\dfrac{2}{3}\), length of its major axis is 4 and its minor axis is parallel to Y-axis, then the equation of the ellipse is
- 1\(\sqrt{5(x-1)^2+9(y-1)^2}=20\)
- 2\(\sqrt{5(x+1)^2+9(y+1)^2}=20\)
- 3\(\sqrt{9(x-1)^2+5(y-1)^2}=20\)
- 4\(\sqrt{9(x+1)^2+5(y+1)^2}=20\)
Q57+1 / 0
For a hyperbola \(\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1\), the distance between its vertex and focus which are lying on the positive side of X-axis is 2. If the length of its latus rectum is 13, then the eccentricity is
- 1\(2.25\)
- 2\(2.50\)
- 3\(1.75\)
- 4\(2.00\)
Q58+1 / 0
If the area of the triangle formed by the points \((0,0,0),\;(1,1,1)\) and \((t,2t,3t)\) is \(\sqrt6\), then the sum of squares of all possible values of \(t\) is
- 1\(13\)
- 2\(5\)
- 3\(20\)
- 4\(8\)
Q59+1 / 0
If \(P(1,2,5),Q(3,0,7),R(6,-3,10)\) are three points on a line and \((\alpha,\beta,\gamma)\) is a point at a distance of 3 units from P on the same line, then the value of \(\alpha+\beta+\gamma\) that lies between 6 and 7 is
- 1\(13-\sqrt3\)
- 2\(8-\sqrt3\)
- 3\(16+\sqrt3\)
- 4\(7-\sqrt2\)
Q60+1 / 0
If the direction cosines of the line common to the planes \(x+2y-z-1=0\) and \(3x-4y+z-5=0\) are \((l,m,n)\), then \(l+m-n=\)
- 1\(\dfrac{6}{\sqrt{30}}\)
- 2\(\dfrac{4}{\sqrt{30}}\)
- 3\(\dfrac{2}{30}\)
- 4\(\dfrac{8}{30}\)
Q61+1 / 0
\([y]\) represents the greatest integer less than or equal to \(y\) and \(\{y\}\) represents the fractional part of \(y\). If
\(\displaystyle\lim_{x\to0^+}\frac{2[1-x]+\{1-x\}}{2[1-x]+\{1-x\}}=11\), then \(\alpha=\)
- 1\(10\)
- 2\(-11\)
- 3\(12\)
- 4\(-9\)
Q62+1 / 0
If \(f(x)=\dfrac{\lambda e^{|x|}+3e^{-x}}{(\lambda+2)e^{|x|}-e^{-x}}\) for \(x\ne0\) and \(f(0)=k,\;k\in\mathbb{R}\) is continuous at \(x=0\), then \(2\lambda=\)
- 1\(5f(0)\)
- 2\(f(0)\)
- 3\(-f(0)\)
- 4\(f(0)\)
Q63+1 / 0
\(f(x)\) is an nth degree polynomial and \(a_1,a_2,\dots,a_n\) are distinct n zeros of \(f(x)\). \(g(x)\) is a polynomial having three zeros common with the zeros of \(f(x)\).
Assertion (A): \(|f(x)|g(x)\) is continuous and differentiable at all \(\alpha_i\)’s.
Reason (R): \(\displaystyle\lim_{x\to a}\frac{|x-a|}{x-a}\) does not exist and \(\displaystyle\lim_{x\to a}|x-a|=0\).
The correct answer is
Assertion (A): \(|f(x)|g(x)\) is continuous and differentiable at all \(\alpha_i\)’s.
Reason (R): \(\displaystyle\lim_{x\to a}\frac{|x-a|}{x-a}\) does not exist and \(\displaystyle\lim_{x\to a}|x-a|=0\).
The correct answer is
- 1Both (A) and (R) are correct, (R) is the correct explanation of (A)
- 2Both (A) and (R) are correct, (R) is not the correct explanation of (A)
- 3(A) is correct, but (R) is not correct
- 4(A) is not correct, but (R) is correct
Q64+1 / 0
If \(y=(e^{2x}-4)(6e^{2x}-5e^{x}+1)\), then \(\left(\dfrac{dy}{dx}\right)_{x=0}-\left(\dfrac{d^2y}{dx^2}\right)_{x=0}=\)
- 1\(0\)
- 2\(-5\)
- 3\(4\)
- 4\(6\)
Q65+1 / 0
If \(f(x)\) is a differentiable function and
\(y=e^{f(x)+e^{f(x)+e^{f(x)+\cdots\infty}}}\), then \(\dfrac{dy}{dx}=\)
- 1\(1+y\)
- 2\(y\)
- 3\(y\)
- 4\(1-y\)
Q66+1 / 0
If \(\dfrac{d}{dx}\!\left(\dfrac{\sec x+\tan x}{\sec x-\tan x}\right)=k\) at \(x=\dfrac{\pi}{4}\), then \(\dfrac{k}{2\sqrt2}-2\sqrt2=\)
- 1\(5\sqrt2\)
- 2\(12\sqrt2\)
- 3\(3\)
- 4\(9\)
Q67+1 / 0
Statement-I: The equation of the tangent to the curve \(y=3x^2-5\) drawn through the point \((1,2)\) is \(y=6x-4\).
Statement-II: If L, M, N are respectively the lengths of the tangent, normal and subnormal drawn to a curve at a point \((\alpha,\beta)\), then \((L)(N)=\beta^2 M\).
Which of the following is correct?
Statement-II: If L, M, N are respectively the lengths of the tangent, normal and subnormal drawn to a curve at a point \((\alpha,\beta)\), then \((L)(N)=\beta^2 M\).
Which of the following is correct?
- 1Both statements I and II are correct
- 2Statement I is correct but statement II is not correct
- 3Statement I is not correct but statement II is correct
- 4Both statements I and II are not correct
Q68+1 / 0
A function is defined as
\[ f(x)=\begin{cases}3x-1, & 0\le x\le2\\ 25(x-1), & 2\le x<\infty\end{cases} \]
For \(f(x)\) in the interval \(\left[\dfrac13,3\right]\):
- 1only Rolle’s theorem is applicable, but Lagrange’s mean value theorem is not applicable
- 2Rolle’s theorem is not applicable but Lagrange’s mean value theorem is applicable
- 3Both Rolle’s and Lagrange’s theorems are applicable
- 4Both Rolle’s and Lagrange’s theorems are not applicable
Q69+1 / 0
In the interval \([-5,5]\), if the function \(f(x)=(x+3)^2(x-2)^3\) is increasing on
\(S=\{x\mid-5\le x<\alpha \text{ and } \beta
- 1\(-108\)
- 2\(108\)
- 3\(72\)
- 4\(-72\)
Q70+1 / 0
If the angle between the curves \(y^2=4x\) and \(y=ax^2-5\) at the point \((1,2)\) is \(\alpha\), then \((a-2)|\tan\alpha|=\)
- 1\(13\)
- 2\(\dfrac{13}{3}\)
- 3\(\dfrac{5}{13}\)
- 4\(\dfrac{13}{5}\)
Q71+1 / 0
A rectangle is inscribed in a parabola \(y=9-x^2\) such that two of its vertices are on the X-axis and another two on the parabola. The dimensions of such rectangle lying above the X-axis and having maximum area is
- 1\(6,\;5\sqrt3\)
- 2\(6,\;2\sqrt3\)
- 3\(9,\;6\)
- 4\(5,\;3\)
Q72+1 / 0
\(\displaystyle\int\sin^{-1}x\,dx-\int\cos^{-1}x\,dx=\)
- 1\(x[\sin^{-1}x-\cos^{-1}x]-2\sqrt{1-x^2}+c\)
- 2\(x\!\left[2\sin^{-1}x+\dfrac{\pi}{2}\right]-2\sqrt{1-x^2}+c\)
- 3\(x[\sin^{-1}x-\cos^{-1}x]+2\sqrt{1-x^2}+c\)
- 4\(x\!\left[\dfrac{\pi}{2}+\cos^{-1}x\right]+2\sqrt{1-x^2}+c\)
Q73+1 / 0
\(\displaystyle\int\frac{dx}{\sqrt{4x^2+11x+6}}=\frac{1}{2}\cosh^{-1}\!\left(\frac{f(x)}{5}\right)+c\) and \(f(1)=19\), then \(f(2)=\)
- 1\(11\)
- 2\(15\)
- 3\(23\)
- 4\(27\)
Q74+1 / 0
If \(\displaystyle\int\log x\sqrt{\left(\frac{\log x}{x}\right)^2+\frac{1}{x^2}}\,dx=\frac{f(x)}{3}\sqrt{1+(\log x)^2}+c\) and \(f(1)=1\), then \(f(e)=\)
- 1\(3\)
- 2\(2\)
- 3\(3\)
- 4\(6\)
Q75+1 / 0
If \(\displaystyle\int\frac{1}{1+\cos x}\,dx=\frac{1}{f\!\left(\frac{x}{2}\right)}+c_1\), then \(\displaystyle\int f(x)\,dx=\)
- 1\(\log|\sin x|+c\)
- 2\(\log|\cos x|+c\)
- 3\(-\operatorname{cosec}^2 x+c\)
- 4\(\tan x+c\)
Q76+1 / 0
Let \(f:[0,1]\to\mathbb{R}\) be a function defined as \(f(x)+f(1-x)=1\). Then \(\displaystyle\int_0^1 f(x)\,dx=\)
- 1\(0\)
- 2\(\dfrac{1}{2}\)
- 3\(1\)
- 4\(2\)
Q77+1 / 0
If \([t]\) denotes greatest integer function, \(\displaystyle\int_{-2}^{2}\left[x^2+[x+1]\right]dx=\)
- 1\(2\tan^{-1}2\)
- 2\(0\)
- 3\(2\)
- 4\(\tan^{-1}2\)
Q78+1 / 0
The area of the region bounded by the curve \(y=|x-2|+|x-8|\), X-axis and the lines \(x=0,\;x=10\) is
- 1\(50\)
- 2\(68\)
- 3\(100\)
- 4\(98\)
Q79+1 / 0
If \(\dfrac{dy}{dx}=(x^3-x)-(1-3x^2)\tan x+(x^3-x)\tan^2 x\) and \(y(1)=0\), then \(\dfrac{64}{\pi}y\!\left(\dfrac{\pi}{4}\right)=\)
- 1\(\pi^2+16\)
- 2\(16-\pi^2\)
- 3\(\pi^2-16\)
- 4\(16\pi^2\)
Q80+1 / 0
If \(\dfrac{dy}{dx}-\dfrac{2x}{x^2+b}y=-2x(x^2+b),\;y(0)=12,\;y(1)=10\), then the sum of all possible values of \(b\) is
- 1\(-1\)
- 2\(1\)
- 3\(3\)
- 4\(5\)
Mathematics · 80 Questions · Correct options highlighted in green

9TH MAY 2026 EAPCET
saamanjans
Table of Contents
ToggleMathematics — Engineering 09 May 2026 · Shift 1
Section 1 · 80 Questions · 80 Marks · Correct option highlighted in green
Mathematics
Section 1 · 80 Questions · 80 Marks · Mandatory
Q1+1 / 0
The domain of the real valued function
\[ f(x)=\cos^{-1}\!\left(\log_5\!\left(\frac{x}{5}\right)\right)+\log_5\!\left(\cos^{-1}\!\left(\frac{x}{5}\right)\right) \]
is
- 1\(\left[\dfrac{1}{5},\,5\right]\)
- 2\([1,\,25]\)
- 3\(\left[\dfrac{1}{5},\,1\right)\)
- 4\([1,\,5)\)
Q2+1 / 0
If \(f:\mathbb{R}\to\mathbb{R}\) is a function defined by \(f(x)=|x|\) for all \(x\in\mathbb{R}\) and \(A\) represents the interval \((0,1)\), then \(f^{-1}(A)=\)
- 1\((0,1)\)
- 2\((-1,1)\)
- 3\((-1,0)\)
- 4\((-1,0)\cup(0,1)\)
Q3+1 / 0
If \(S(n):2^n
- 1\(1\)
- 2\(2\)
- 3\(3\)
- 4\(4\)
Q4+1 / 0
If \(A=\begin{bmatrix}\cos\alpha&0&\sin\alpha\\0&1&0\\-\sin\alpha&0&\cos\alpha\end{bmatrix}\) and \(A^2=A^T\) for one value of \(\alpha\in(0,\pi)\), then \(A^3=\)
- 1\(I\)
- 2\(A\)
- 3\(A^2\)
- 4\(A^T\)
Q5+1 / 0
Let \(A\) be a \(3\times3\) matrix such that \(\det(A)=-1\). If \(B^{-1}=\operatorname{Adj}\!\big(A\,\operatorname{Adj}(A^2)\big)\), then \(\det\big((\det A)B\big)=\)
- 1\(|A|\)
- 2\(|B|\)
- 3\(|A+B|\)
- 4\(|A-B|\)
Q6+1 / 0
Consider the system of linear equations (L): \(2x-y-z=-3,\; x+2y+z=4,\; 3x+y+kz=3\). Let \(k\in\mathbb{N}\) and \(1\le k\le 2026\).
\(A=\{k\mid L \text{ has no solution}\}\), \(B=\{k\mid L \text{ has unique solution}\}\), \(C=\{k\mid L \text{ has infinite solutions}\}\).
\(n(A)+n(B)+n(C)=\)
\(A=\{k\mid L \text{ has no solution}\}\), \(B=\{k\mid L \text{ has unique solution}\}\), \(C=\{k\mid L \text{ has infinite solutions}\}\).
\(n(A)+n(B)+n(C)=\)
- 1\(2027\)
- 2\(2026\)
- 3\(2029\)
- 4\(2028\)
Q7+1 / 0
Let \(A\) be a \(3\times3\) matrix. If
\[ A\begin{bmatrix}0\\0\\1\end{bmatrix}=\begin{bmatrix}1\\2\\3\end{bmatrix},\quad
A\begin{bmatrix}1\\0\\1\end{bmatrix}=\begin{bmatrix}1\\0\\-1\end{bmatrix},\quad
A\begin{bmatrix}1\\1\\0\end{bmatrix}=\begin{bmatrix}1\\1\\0\end{bmatrix} \]
then the rank of \((A-I)\) is
- 1\(3\)
- 2\(2\)
- 3\(1\)
- 4\(0\)
Q8+1 / 0
If \(A=\{z=x+iy \mid |z-4|<|z-2| \;\&\; |z-7|>|z-3|\}\),
\(B=\{z=x+iy \mid -3\le y\le 3,\; x\in\mathbb{N},\; y\in\mathbb{N}\}\),
\(C=A\cap B\), then \(n(C)=\)
\(B=\{z=x+iy \mid -3\le y\le 3,\; x\in\mathbb{N},\; y\in\mathbb{N}\}\),
\(C=A\cap B\), then \(n(C)=\)
- 1\(11\)
- 2\(16\)
- 3\(7\)
- 4\(12\)
Q9+1 / 0
\(z_1\) and \(z_2\) are two complex numbers such that \(|z_1-\alpha|=|z_2-\alpha|\) for \(\alpha\in\mathbb{R}\). If \(\operatorname{Arg}(z_1-\alpha)+\operatorname{Arg}(z_2-\alpha)=\dfrac{\pi}{2}\), then \(\dfrac{z_1-\alpha}{z_2-\alpha}=\)
- 1\(\alpha\)
- 2\(i\)
- 3\(-i\)
- 4\(i\alpha\)
Q10+1 / 0
If \(\omega\) is the complex cube root of 1, then
\[ (1+\omega)(1+\omega^2)(1+\omega^4)(1+\omega^5)(1+\omega^7)(1+\omega^8)\cdots 2n \text{ factors} = \]
- 1\(-1\)
- 2\(0\)
- 3\(1\)
- 4\(2\)
Q11+1 / 0
\(m,n,k\) are integers and \(9.5\le n\le 12\). If
\[ \frac{(\cos\theta+i\sin\theta)^m}{(\sin\theta+i\cos\theta)^n}=k(\sin 170^\circ – i\cos 170^\circ), \]
then \(n-m-k=\)
- 1\(6\)
- 2\(12\)
- 3\(5\)
- 4\(7\)
Q12+1 / 0
If \(a\in\mathbb{Z}\) and the equation \((x-a)(x-10)+1=0\) has integral roots, then the values of \(a\) are
- 1\(8,\;12\)
- 2\(12,\;10\)
- 3\(10,\;8\)
- 4\(9,\;11\)
Q13+1 / 0
If \(\alpha,\beta\) are the rational roots and \(l,m\) are the irrational roots of
\[ (x^2-9x+11)^2-(x-4)(x-5)=3, \]
then \(\alpha+\beta+l=\)
- 1\(2\)
- 2\(16\)
- 3\(8\)
- 4\(12\)
Q14+1 / 0
Let \(\alpha,\beta,\gamma,\delta\) be the roots of \(4x^4+8x^3-17x^2-12x+9=0\). If
\(4(\alpha+4)(\beta+4)(\gamma+4)(\delta+4)=k\), then \(k=\)
- 1\(25\)
- 2\(35\)
- 3\(297\)
- 4\(105\)
Q15+1 / 0
The number of real roots of the equation \(x^7+3x^5-13x^3-15x=0\) is
- 1\(5\)
- 2\(1\)
- 3\(7\)
- 4\(3\)
Q16+1 / 0
The number of integral solutions of the equation \(x+y+z=13\) such that \(1\le x\le9,\;0\le y\le9,\;0\le z\le9\) is
- 1\(105\)
- 2\(66\)
- 3\(69\)
- 4\(83\)
Q17+1 / 0
If \(\dfrac{{}^{n-1}C_{r-1}}{{}^{n}C_r}=\dfrac{3}{5}\) and \(\dfrac{{}^{n+1}C_{r+1}}{{}^{n}C_r}=\dfrac{11}{7}\), then
\({}^{n}C_{r+3}\div{}^{r}C_{n/2}=\)
- 1\(\dfrac{3}{5}\)
- 2\(12\)
- 3\(8\)
- 4\(\dfrac{5}{3}\)
Q18+1 / 0
There are 7 men and 5 women in a park. The number of ways of arranging them around a circular path such that 4 particular persons which include 2 particular men and 2 particular women never stand together is
- 1\(11879(8!)\)
- 2\(966(8!)\)
- 3\(986(8!)\)
- 4\(494(4!)(8!)\)
Q19+1 / 0
Let \([t]\) represent the greatest integer less than or equal to \(t\). If \(x=(7\sqrt5+15)^9\) and \(y=(5\sqrt7+13)^{11}\), then \([x]\) and \([y]\) are
- 1even integer and odd integer respectively
- 2odd integer and even integer respectively
- 3both odd integers
- 4both even integers
Q20+1 / 0
If \(\alpha_n\) is the coefficient of \(x^n\) in the expansion of \((1-x)^{-5}\) and \(\beta_n\) is the coefficient of \(x^n\) in the expansion of \((1-x)^4\), then \(\alpha_{12}+\beta_{13}=\)
- 1\(\alpha_{13}\)
- 2\(\beta_{13}\)
- 3\(\alpha_{25}\)
- 4\(\beta_{25}\)
Q21+1 / 0
If \(\dfrac{x^2+1}{(x^4+5x^2+6)(x^6+x^4)}=\dfrac{A}{x^4}+\dfrac{B}{x^2}+\dfrac{C}{x^2+2}+\dfrac{D}{x^2+3}\), then \(A-B=\)
- 1\(13\)
- 2\(36\)
- 3\(2\)
- 4\(1\)
Q22+1 / 0
If \(\theta=\dfrac{11\pi}{7}\), then \(\dfrac{1+\cos 8\theta}{\cot^2 4\theta}+\dfrac{1-\cos 8\theta}{\tan^2 4\theta}=\)
- 1\(\dfrac{\sin(\pi/7)}{7}\)
- 2\(\dfrac{2\pi}{7}\)
- 3\(2\)
- 4\(1\)
Q23+1 / 0
If \(\alpha\) and \(\beta\) are acute angles and \(\cos\alpha(1+\tan\alpha\tan\beta)=1\), then
\(\sin\!\left(\dfrac{\alpha-2\beta}{3}\right)=\)
- 1\(\dfrac{1}{2}\)
- 2\(\dfrac{\sqrt3}{2}\)
- 3\(\dfrac{3}{5}\)
- 4\(0\)
Q24+1 / 0
The number of values of \(\theta\) lying in \([0,2\pi]\) for which \(\sin 3\theta\) attains its maximum when
\[ \left|\sin\theta\,\sin\!\left(\frac{\pi}{3}-\theta\right)\sin\!\left(\frac{\pi}{3}+\theta\right)\right|\le\frac{1}{8} \]
is
- 1\(4\)
- 2\(2\)
- 3\(6\)
- 4\(8\)
Q25+1 / 0
If \(\cos 6\theta+\cos 4\theta+\cos 2\theta+1=0\) for \(0\le\theta\le\pi\), then \(\theta=\)
- 1\(\dfrac{\pi}{6},\dfrac{\pi}{4},\dfrac{\pi}{2},\dfrac{3\pi}{4},\dfrac{5\pi}{6}\)
- 2\(\dfrac{\pi}{3},\dfrac{\pi}{2},\dfrac{2\pi}{3}\)
- 3\(\dfrac{\pi}{6},\dfrac{\pi}{3},\dfrac{2\pi}{3}\)
- 4\(\dfrac{\pi}{4},\dfrac{\pi}{2},\dfrac{3\pi}{4}\)
Q26+1 / 0
The number of real solutions of the equation \(\sin^{-1}(2-x)-2\sin^{-1}x=\pm\dfrac{\pi}{2}\) is
- 1\(0\)
- 2\(1\)
- 3\(2\)
- 4\(3\)
Q27+1 / 0
If \(\alpha\) is a real number and \(2\sinh^2 x-3\cosh x+\alpha=0\) has a solution, then the range of \(\alpha\) is
- 1\([3,\infty)\)
- 2\(\left(0,\dfrac{25}{8}\right)\)
- 3\(\left[3,\dfrac{25}{8}\right]\)
- 4\((-\infty,3]\)
Q28+1 / 0
In a triangle ABC, if \(a=2,\;\sin A=\dfrac{2}{3},\;B=\dfrac{\pi}{3}\), then \(\sqrt5\,b-3c=\)
- 1\(-\sqrt3\)
- 2\(\sqrt3\)
- 3\(\sqrt5-\sqrt3\)
- 4\(\sqrt2\)
Q29+1 / 0
In a triangle ABC, if \((b-c)\cos\dfrac{A}{2}=k\sin\dfrac{B-C}{2}\), then \(\dfrac{k}{\sin A}=\)
- 1\(\sqrt{b}\)
- 2\(\sqrt{2R}\sin A\)
- 3\(\sqrt{2R}\)
- 4\(\sqrt{a+c}\)
Q30+1 / 0
Let \(\vec{OA}=\mathbf{i}+2\mathbf{j}+2\mathbf{k},\;\vec{OB}=3\mathbf{i}+4\mathbf{k}\). If \(x\mathbf{i}+y\mathbf{j}+z\mathbf{k}\) is the vector along the bisector of \(\angle AOB\) and of length 2 units, then a possible value of \(x+y+z\) is
- 1\(\dfrac{4}{30}\)
- 2\(\dfrac{46}{295}\)
- 3\(\dfrac{30}{295}\)
- 4\(\dfrac{1}{15}\)
Q31+1 / 0
If the line \(\vec r=\vec a+t\vec b\) lies on the plane \(\vec r\cdot\vec n=p\), then \(p=\)
- 1\(1\)
- 2\(2\)
- 3\(3\)
- 4\(0\)
Q32+1 / 0
If \(\vec{AB}=\mathbf{i}+\mathbf{j}-2\mathbf{k},\;\vec{CB}=2\mathbf{i}-\mathbf{j}+a\mathbf{k}\;(a\in\mathbb{Z})\) are two sides of a triangle ABC and the angle between these two sides is \(\dfrac{\pi}{3}\), then the length of its third side is
- 1\(6\)
- 2\(2\sqrt6\)
- 3\(\sqrt6\)
- 4\(3\sqrt6\)
Q33+1 / 0
If the shortest distance between the skew lines \(\vec r=\mathbf{i}+\mathbf{j}+\mathbf{k}+t(3\mathbf{i}+2\mathbf{j}+\mathbf{k})\) and \(\vec r=\mathbf{i}-\mathbf{j}+x\mathbf{k}+s(\mathbf{i}+2\mathbf{j}+3\mathbf{k})\) is at most \(2\sqrt6\) units, then all the values of \(x\) lie in the interval
- 1\([-9,\,15]\)
- 2\([-15,\,9]\)
- 3\((-\infty,\,-15)\)
- 4\(\mathbb{R}-[-11,\,9]\)
Q34+1 / 0
\(\vec a,\vec b,\vec c\) are non-coplanar vectors. If \(\vec x=2\vec a+3\vec b+4\vec c,\;\vec y=3\vec a+4\vec b+5\vec c,\;\vec z=4\vec a+5\vec b+6\vec c\), then \([\vec x\;\vec y\;\vec z]=\)
- 1\(0\)
- 2\(9[a\;b\;c]\)
- 3\(15[a\;b\;c]\)
- 4\(12[a\;b\;c]\)
Q35+1 / 0
The mean deviation from the median of the given frequency distribution is
| Class interval | 1–7 | 7–13 | 13–19 | 19–25 | 25–31 |
|---|---|---|---|---|---|
| Frequency | 4 | 5 | 3 | 6 | 2 |
- 1\(7\)
- 2\(7.5\)
- 3\(6\)
- 4\(5\)
Q36+1 / 0
Bag A contains 5 white and 2 black balls. Bag B contains 2 white and 5 black balls. Two balls are randomly chosen from bag A and placed in bag B. Now a ball is drawn randomly from bag B and found that it is white. The probability that the two balls drawn from bag A are of different colour is
- 1\(21\)
- 2\(63\)
- 3\(12\)
- 4\(189\)
Q37+1 / 0
If A, B, C are three mutually exclusive and exhaustive events such that \(P(A):P(B):P(C)=1:1:m\), then
\(P(A\cup B)+P(B\cup C)+P(C\cup A)+P(A\cup B\cup C)=\)
- 1\(3\)
- 2\(3\)
- 3\(4\)
- 4\(1\)
Q38+1 / 0
If \(P(A)=\dfrac{3}{8},\;P(A\mid B)=P(B\mid A)=\dfrac{3}{5}\), then \(P(A\cap B)+P(B)=\)
- 1\(40\)
- 2\(13\)
- 3\(\dfrac{3}{14}\)
- 4\(\dfrac{5}{12}\)
Q39+1 / 0
Probability for a person A to have success in one trial is \(\dfrac{2}{5}\). In 7 Bernoulli trials, if the probability that A has \(k\) successes is to be highest probability, then \(k=\)
- 1\(3\)
- 2\(4\)
- 3\(5\)
- 4\(7\)
Q40+1 / 0
Let \(p\) be the probability of getting a success in one trial and \(0
- 1\(1-p\)
- 2\(p\)
- 3\(p^2\)
- 4\(\dfrac{1}{p}\)
Q41+1 / 0
If \(S=\{(x,y)\mid x=2\cos t+3\sin t,\;y=3\cos t+2\sin t,\;t\in\mathbb{R}\}\), then the points of S lie on the curve
- 1\(x^2+y^2-5xy+1=0\)
- 2\(x^2+y^2+5xy-1=0\)
- 3\(x^2+y^2=13\)
- 4\(x^2-y^2=5\)
Q42+1 / 0
If the coordinate axes are rotated about the origin in the positive direction through an angle \(60^\circ\) to get the transformed equation of \(x^2+y^2-4x-8y+16=0\) as \(x^2+y^2+2Gx+2Fy+C=0\), then \(G+F+C=\)
- 1\(13-\sqrt3\)
- 2\(16+2\)
- 3\(14-2\)
- 4\(15+\sqrt3\)
Q43+1 / 0
\((3a+1)x+(7a+2)y=17a+5\), \(a\) being a parameter, represents a family of concurrent lines. If \(d\) is the distance from the point \((3,1)\) to a line of this family having slope 1, then \(2d^2=\)
- 1\(4\)
- 2\(3\)
- 3\(9\)
- 4\(16\)
Q44+1 / 0
Let a ray of light passing through a point \((7,2)\) reflects on the line \(2x+y=1\) and the reflected ray passes through \((3,10)\). The equation of the incident ray is
- 1\(x-4y+1=0\)
- 2\(3x-2y=17\)
- 3\(x+y=9\)
- 4\(x+8y-23=0\)
Q45+1 / 0
Let ABC be an isosceles triangle. If B is a point on the positive X-axis, \(a=4\sqrt3\), \(c\) is an integer, \(\angle A=120^\circ\) and \(A=(-1,0)\), then the distance of C from the origin is
- 1\(15\)
- 2\(48\)
- 3\(21\)
- 4\(26\)
Q46+1 / 0
One of the pair of lines \(x^2-3y^2-4x-6\sqrt3 y-5=0\) is \(x+by+c=0\;(b<0)\). If the other line intersects the curve \(x^2-5y^2-4x=0\) at two points A and B, then \(\angle AOB=\)
- 1\(\dfrac{\pi}{4}\)
- 2\(\dfrac{\pi}{3}\)
- 3\(\dfrac{\pi}{6}\)
- 4\(\dfrac{\pi}{2}\)
Q47+1 / 0
If a circle inscribed in the parabola \(y^2=4ax\;(a>0)\) passes through its focus, then the equation of that circle is
- 1\((x-5a)^2+y^2=16a^2\)
- 2\((x-4a)^2+y^2=9a^2\)
- 3\((x+7a)^2+y^2=64a^2\)
- 4\((x+a)^2+y^2=4a^2\)
Q48+1 / 0
Let \((-h,-k)\) (h, k integers) be the centre and \(r\) the radius of a circle. If \(3x+4y-24=0,\;3x-4y-32=0\) are two tangents and \(4x+3y-1=0\) is a normal, then \(r+h+k=\)
- 1\(8\)
- 2\(7\)
- 3\(5\)
- 4\(4\)
Q49+1 / 0
Let P be any point on the circle \(x^2+y^2=16\) and \(A=(1,2)\). If the locus of the point which divides the line segment AP in the ratio 3:2 is a circle, then its radius is
- 1\(5\)
- 2\(4\)
- 3\(\dfrac{12}{5}\)
- 4\(\dfrac{13}{4}\)
Q50+1 / 0
If the line \(4x-3y+c=0\;(c<-10)\) makes an intercept of length 10 units on the circle \(x^2+y^2-2x+4y-23=0\), then \(c=\)
- 1\(-10-\sqrt{175}\)
- 2\(-10-\sqrt{75}\)
- 3\(-10-\sqrt{125}\)
- 4\(-10-\sqrt{150}\)
Q51+1 / 0
The tangent drawn at a point P on the circle \(x^2+y^2+6x+6y-2=0\) cuts the line \(5x-2y+6=0\) at Q. If \(PQ=5\), then a point Q having integral coordinates is
- 1\((0,3)\)
- 2\((2,8)\)
- 3\((-2,-2)\)
- 4\((-4,-7)\)
Q52+1 / 0
If two vertices of a quadrilateral are the centres of the circles \(S\equiv x^2+y^2-2x-2y-2=0,\;S’\equiv x^2+y^2-6x-6y+14=0\) and the other two vertices are the points of intersection of S=0 and S’=0, then the area of the quadrilateral is
- 1\(4\)
- 2\(5\sqrt2\)
- 3\(\dfrac{7}{5}\)
- 4\(\dfrac{5}{2}\)
Q53+1 / 0
\(y=4\) is the directrix of the parabola \(x^2+8x+12y+k=0\). If \(l\) is the length of its latus rectum, then \(l-k=\)
- 1\(4\)
- 2\(8\)
- 3\(12\)
- 4\(6\)
Q54+1 / 0
\((1,1)\) is the focus of the parabola \(y^2-4ax-2ay+a^2=0\). If the circles \((x-\alpha)^2+(y-\beta)^2=r^2\) (\(\alpha,\beta\) parameters) touch the X-axis and the axis of the given parabola, then \(\{(\alpha,\beta)\mid\alpha,\beta\in\mathbb{R}\}\) is
- 1\(y=\dfrac{1}{2}\)
- 2\(x^2+y^2=\dfrac{1}{4}\)
- 3\(x^2+y^2=\dfrac{1}{4}\)
- 4\(y^2=2x\)
Q55+1 / 0
The area of the rectangle formed by the tangents drawn at the ends of both major and minor axes of an ellipse is 24. If the eccentricity of the ellipse is \(\dfrac{1}{4}\), then the equation of the ellipse is
- 1\(\dfrac{x^2}{48}+\dfrac{y^2}{45}=1\)
- 2\(\dfrac{x^2}{16}+\dfrac{y^2}{15}=1\)
- 3\(\dfrac{x^2}{24}+\dfrac{y^2}{45}=\dfrac{1}{\sqrt5}\)
- 4\(\sqrt{\dfrac{x^2}{8\sqrt3}}+\sqrt{\dfrac{2y^2}{15\sqrt3}}=\dfrac{1}{\sqrt5}\)
Q56+1 / 0
The centre of the ellipse lies on the lines \(2x+3y=5\) and \(x+3y=4\). If the eccentricity is \(\dfrac{2}{3}\), length of its major axis is 4 and its minor axis is parallel to Y-axis, then the equation of the ellipse is
- 1\(\sqrt{5(x-1)^2+9(y-1)^2}=20\)
- 2\(\sqrt{5(x+1)^2+9(y+1)^2}=20\)
- 3\(\sqrt{9(x-1)^2+5(y-1)^2}=20\)
- 4\(\sqrt{9(x+1)^2+5(y+1)^2}=20\)
Q57+1 / 0
For a hyperbola \(\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1\), the distance between its vertex and focus which are lying on the positive side of X-axis is 2. If the length of its latus rectum is 13, then the eccentricity is
- 1\(2.25\)
- 2\(2.50\)
- 3\(1.75\)
- 4\(2.00\)
Q58+1 / 0
If the area of the triangle formed by the points \((0,0,0),\;(1,1,1)\) and \((t,2t,3t)\) is \(\sqrt6\), then the sum of squares of all possible values of \(t\) is
- 1\(13\)
- 2\(5\)
- 3\(20\)
- 4\(8\)
Q59+1 / 0
If \(P(1,2,5),Q(3,0,7),R(6,-3,10)\) are three points on a line and \((\alpha,\beta,\gamma)\) is a point at a distance of 3 units from P on the same line, then the value of \(\alpha+\beta+\gamma\) that lies between 6 and 7 is
- 1\(13-\sqrt3\)
- 2\(8-\sqrt3\)
- 3\(16+\sqrt3\)
- 4\(7-\sqrt2\)
Q60+1 / 0
If the direction cosines of the line common to the planes \(x+2y-z-1=0\) and \(3x-4y+z-5=0\) are \((l,m,n)\), then \(l+m-n=\)
- 1\(\dfrac{6}{\sqrt{30}}\)
- 2\(\dfrac{4}{\sqrt{30}}\)
- 3\(\dfrac{2}{30}\)
- 4\(\dfrac{8}{30}\)
Q61+1 / 0
\([y]\) represents the greatest integer less than or equal to \(y\) and \(\{y\}\) represents the fractional part of \(y\). If
\(\displaystyle\lim_{x\to0^+}\frac{2[1-x]+\{1-x\}}{2[1-x]+\{1-x\}}=11\), then \(\alpha=\)
- 1\(10\)
- 2\(-11\)
- 3\(12\)
- 4\(-9\)
Q62+1 / 0
If \(f(x)=\dfrac{\lambda e^{|x|}+3e^{-x}}{(\lambda+2)e^{|x|}-e^{-x}}\) for \(x\ne0\) and \(f(0)=k,\;k\in\mathbb{R}\) is continuous at \(x=0\), then \(2\lambda=\)
- 1\(5f(0)\)
- 2\(f(0)\)
- 3\(-f(0)\)
- 4\(f(0)\)
Q63+1 / 0
\(f(x)\) is an nth degree polynomial and \(a_1,a_2,\dots,a_n\) are distinct n zeros of \(f(x)\). \(g(x)\) is a polynomial having three zeros common with the zeros of \(f(x)\).
Assertion (A): \(|f(x)|g(x)\) is continuous and differentiable at all \(\alpha_i\)’s.
Reason (R): \(\displaystyle\lim_{x\to a}\frac{|x-a|}{x-a}\) does not exist and \(\displaystyle\lim_{x\to a}|x-a|=0\).
The correct answer is
Assertion (A): \(|f(x)|g(x)\) is continuous and differentiable at all \(\alpha_i\)’s.
Reason (R): \(\displaystyle\lim_{x\to a}\frac{|x-a|}{x-a}\) does not exist and \(\displaystyle\lim_{x\to a}|x-a|=0\).
The correct answer is
- 1Both (A) and (R) are correct, (R) is the correct explanation of (A)
- 2Both (A) and (R) are correct, (R) is not the correct explanation of (A)
- 3(A) is correct, but (R) is not correct
- 4(A) is not correct, but (R) is correct
Q64+1 / 0
If \(y=(e^{2x}-4)(6e^{2x}-5e^{x}+1)\), then \(\left(\dfrac{dy}{dx}\right)_{x=0}-\left(\dfrac{d^2y}{dx^2}\right)_{x=0}=\)
- 1\(0\)
- 2\(-5\)
- 3\(4\)
- 4\(6\)
Q65+1 / 0
If \(f(x)\) is a differentiable function and
\(y=e^{f(x)+e^{f(x)+e^{f(x)+\cdots\infty}}}\), then \(\dfrac{dy}{dx}=\)
- 1\(1+y\)
- 2\(y\)
- 3\(y\)
- 4\(1-y\)
Q66+1 / 0
If \(\dfrac{d}{dx}\!\left(\dfrac{\sec x+\tan x}{\sec x-\tan x}\right)=k\) at \(x=\dfrac{\pi}{4}\), then \(\dfrac{k}{2\sqrt2}-2\sqrt2=\)
- 1\(5\sqrt2\)
- 2\(12\sqrt2\)
- 3\(3\)
- 4\(9\)
Q67+1 / 0
Statement-I: The equation of the tangent to the curve \(y=3x^2-5\) drawn through the point \((1,2)\) is \(y=6x-4\).
Statement-II: If L, M, N are respectively the lengths of the tangent, normal and subnormal drawn to a curve at a point \((\alpha,\beta)\), then \((L)(N)=\beta^2 M\).
Which of the following is correct?
Statement-II: If L, M, N are respectively the lengths of the tangent, normal and subnormal drawn to a curve at a point \((\alpha,\beta)\), then \((L)(N)=\beta^2 M\).
Which of the following is correct?
- 1Both statements I and II are correct
- 2Statement I is correct but statement II is not correct
- 3Statement I is not correct but statement II is correct
- 4Both statements I and II are not correct
Q68+1 / 0
A function is defined as
\[ f(x)=\begin{cases}3x-1, & 0\le x\le2\\ 25(x-1), & 2\le x<\infty\end{cases} \]
For \(f(x)\) in the interval \(\left[\dfrac13,3\right]\):
- 1only Rolle’s theorem is applicable, but Lagrange’s mean value theorem is not applicable
- 2Rolle’s theorem is not applicable but Lagrange’s mean value theorem is applicable
- 3Both Rolle’s and Lagrange’s theorems are applicable
- 4Both Rolle’s and Lagrange’s theorems are not applicable
Q69+1 / 0
In the interval \([-5,5]\), if the function \(f(x)=(x+3)^2(x-2)^3\) is increasing on
\(S=\{x\mid-5\le x<\alpha \text{ and } \beta
- 1\(-108\)
- 2\(108\)
- 3\(72\)
- 4\(-72\)
Q70+1 / 0
If the angle between the curves \(y^2=4x\) and \(y=ax^2-5\) at the point \((1,2)\) is \(\alpha\), then \((a-2)|\tan\alpha|=\)
- 1\(13\)
- 2\(\dfrac{13}{3}\)
- 3\(\dfrac{5}{13}\)
- 4\(\dfrac{13}{5}\)
Q71+1 / 0
A rectangle is inscribed in a parabola \(y=9-x^2\) such that two of its vertices are on the X-axis and another two on the parabola. The dimensions of such rectangle lying above the X-axis and having maximum area is
- 1\(6,\;5\sqrt3\)
- 2\(6,\;2\sqrt3\)
- 3\(9,\;6\)
- 4\(5,\;3\)
Q72+1 / 0
\(\displaystyle\int\sin^{-1}x\,dx-\int\cos^{-1}x\,dx=\)
- 1\(x[\sin^{-1}x-\cos^{-1}x]-2\sqrt{1-x^2}+c\)
- 2\(x\!\left[2\sin^{-1}x+\dfrac{\pi}{2}\right]-2\sqrt{1-x^2}+c\)
- 3\(x[\sin^{-1}x-\cos^{-1}x]+2\sqrt{1-x^2}+c\)
- 4\(x\!\left[\dfrac{\pi}{2}+\cos^{-1}x\right]+2\sqrt{1-x^2}+c\)
Q73+1 / 0
\(\displaystyle\int\frac{dx}{\sqrt{4x^2+11x+6}}=\frac{1}{2}\cosh^{-1}\!\left(\frac{f(x)}{5}\right)+c\) and \(f(1)=19\), then \(f(2)=\)
- 1\(11\)
- 2\(15\)
- 3\(23\)
- 4\(27\)
Q74+1 / 0
If \(\displaystyle\int\log x\sqrt{\left(\frac{\log x}{x}\right)^2+\frac{1}{x^2}}\,dx=\frac{f(x)}{3}\sqrt{1+(\log x)^2}+c\) and \(f(1)=1\), then \(f(e)=\)
- 1\(3\)
- 2\(2\)
- 3\(3\)
- 4\(6\)
Q75+1 / 0
If \(\displaystyle\int\frac{1}{1+\cos x}\,dx=\frac{1}{f\!\left(\frac{x}{2}\right)}+c_1\), then \(\displaystyle\int f(x)\,dx=\)
- 1\(\log|\sin x|+c\)
- 2\(\log|\cos x|+c\)
- 3\(-\operatorname{cosec}^2 x+c\)
- 4\(\tan x+c\)
Q76+1 / 0
Let \(f:[0,1]\to\mathbb{R}\) be a function defined as \(f(x)+f(1-x)=1\). Then \(\displaystyle\int_0^1 f(x)\,dx=\)
- 1\(0\)
- 2\(\dfrac{1}{2}\)
- 3\(1\)
- 4\(2\)
Q77+1 / 0
If \([t]\) denotes greatest integer function, \(\displaystyle\int_{-2}^{2}\left[x^2+[x+1]\right]dx=\)
- 1\(2\tan^{-1}2\)
- 2\(0\)
- 3\(2\)
- 4\(\tan^{-1}2\)
Q78+1 / 0
The area of the region bounded by the curve \(y=|x-2|+|x-8|\), X-axis and the lines \(x=0,\;x=10\) is
- 1\(50\)
- 2\(68\)
- 3\(100\)
- 4\(98\)
Q79+1 / 0
If \(\dfrac{dy}{dx}=(x^3-x)-(1-3x^2)\tan x+(x^3-x)\tan^2 x\) and \(y(1)=0\), then \(\dfrac{64}{\pi}y\!\left(\dfrac{\pi}{4}\right)=\)
- 1\(\pi^2+16\)
- 2\(16-\pi^2\)
- 3\(\pi^2-16\)
- 4\(16\pi^2\)
Q80+1 / 0
If \(\dfrac{dy}{dx}-\dfrac{2x}{x^2+b}y=-2x(x^2+b),\;y(0)=12,\;y(1)=10\), then the sum of all possible values of \(b\) is
- 1\(-1\)
- 2\(1\)
- 3\(3\)
- 4\(5\)
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